Here is an example array I have:
[["", "A"], ["B", ""], ["A", ""], ["", "A"]]
I am looking to remove the first and third arrays as they are symmetrical, resulting in this array:
[["B", ""], ["", "A"]]
If anyone knows how to achieve this, please share. I can utilize any data structure and algorithms without concern for time and space complexity.
One potential resolution,
See it in action:
const info = [["", "A"], ["B", ""], ["A", ""], ["", "A"]]
const facts = [["", "A"], ["B", ""], ["A", ""], ["", "A"], ["", "B"]]
const areOpposite = (x, y) => JSON.stringify(x) === JSON.stringify(y.reverse());
const getMirrorIndices = (data) => data.reduce((acc, x, indexX) => {
data.forEach((y, indexY) => (areOpposite(x, y)) && acc.push([indexX, indexY]));
return acc;
}, []);
const duoToErase = (data) => data.at(0).sort((x, y) => y - x);
const eraseOpposites = (data) => {
const collection = [...data];
let indices = getMirrorIndices(collection);
while(indices.length > 0) {
duoToErase(indices).forEach(index => collection.splice(index, 1));
indices = getMirrorIndices(collection);
};
return collection;
};
console.log(eraseOpposites(info));
console.log(eraseOpposites(facts));.as-console-wrapper { max-height: 100% !important; top: 0 }After experimenting with it today, I came up with my own solution:
let elements = [["", "A"], ["B", ""], ["A", ""], ["", "A"],["", "B"],["","C"],["C",""],["","B"]];
const removeSymmetricElements = (array) => {
let result = [];
for (let i = 0; i < array.length; i++) {
if (!isSymmetricElementIncluded(result, array[i])) {
result = [...result, array[i]];
} else {
result = result.filter(
(item) => item[0] !== array[i][1] || item[1] !== array[i][0]
);
}
}
return result;
function isSymmetricElementIncluded(a, b) {
for (let i = 0; i < a.length; i++) {
if (a[i][0] === b[1] && a[i][1] === b[0]) {
return true;
}
}
return false;
}
};
console.log(removeSymmetricElements(elements))
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