What is the best method for capturing the line delimiter character(s) in a manner that is not dependent on the platform being

When using the regular expression /^\S+\s*$/m.exec("a\nb\n")[0], it only returns "a" without including the line delimiter, even though \s should match \n.

After some experimentation, I discovered that modifying the expression like this:

/^\S+\s*$\n\r?/m.exec("a\nb\n")[0]
achieves the desired result.

However, this modification creates a regex that is platform-dependent.

Is there a way to include the line delimiting character(s) in the match in a manner that is platform-independent?

Answer №1

Apologies, I was able to figure it out on my own.

I've discovered that instead of looking for the end of a line, it might be more effective to search for the beginning of the next line. For example:

/^\S+\s*^/m.exec("a\nb\n")[0]

This code snippet will return "a\n".

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