What is the approach for obtaining the specified arrays using two pointer methodology in JavaScript?

Question

What is the approach for obtaining the specified arrays using two pointer methodology in JavaScript?

input [1,8,9]

output [[1],[1,8],[1,8,9],[8],[8,9],[9]]

It appears to be a subset array, but I am aiming to achieve this output using a two-pointer approach. Let's assign leftP=0, rightP=0; and then utilizing a for loop, the rightP will iterate until the end of the array and then the leftP will move by 1...

1 -> [1], [1,8],[1,8,9]

8 -> [8],[8,9]

9 -> [9]


function solution(arr) {
   let totalArr = [];
   let leftP = 0;

   for(let rightP=0; rightP<arr.length; rightP++) {
      totalArr.push(arr[rightP]);

      // this is where I am encountering an obstacle
      while()

   }
}

javascript arrays

Answer 1

Answer №1

To achieve this task, you can utilize two for loops as demonstrated below:

i represents leftP and j represents rightP

const sampleArray = [1, 8, 9];

const outcome = [];

for (let i = 0; i < sampleArray.length; ++i) {
  let tempArr = [sampleArray[i]];
  outcome.push([...tempArr]);
  for (let j = i + 1; j < sampleArray.length; ++j) {
    tempArr.push(sampleArray[j]);
    outcome.push([...tempArr]);
  }
  tempArr = [];
}

console.log(outcome);

/* This CSS snippet is not related to the solution. It is only for formatting purposes. Please disregard it */
.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

To achieve this task, you can utilize two for loops as demonstrated below:

i represents leftP and j represents rightP

const sampleArray = [1, 8, 9];

const outcome = [];

for (let i = 0; i < sampleArray.length; ++i) {
  let tempArr = [sampleArray[i]];
  outcome.push([...tempArr]);
  for (let j = i + 1; j < sampleArray.length; ++j) {
    tempArr.push(sampleArray[j]);
    outcome.push([...tempArr]);
  }
  tempArr = [];
}

console.log(outcome);

/* This CSS snippet is not related to the solution. It is only for formatting purposes. Please disregard it */
.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

Answer №2

To solve this problem, simply utilize the two pointers technique!

Here is a functional solution:

const arr = [1, 8, 9];

const solve = (arr) => {
  const resultArr = [];

  for (let i = 0; i < arr.length; i++) {
    for (let j = i + 1; j <= arr.length; j++) {
      resultArr.push(arr.slice(i, j));
    }
  }

  return resultArr;
};

console.log(solve(arr));

Answer 4

To solve this problem, simply utilize the two pointers technique!

Here is a functional solution:

const arr = [1, 8, 9];

const solve = (arr) => {
  const resultArr = [];

  for (let i = 0; i < arr.length; i++) {
    for (let j = i + 1; j <= arr.length; j++) {
      resultArr.push(arr.slice(i, j));
    }
  }

  return resultArr;
};

console.log(solve(arr));

Answer 5

Answer №3

To convert your reasoning into code, I would suggest using two nested loops.

function generateSubarrays(arr) {
  let allSubarrays = [];
  for (let start = 0; start < arr.length; start++) {
    allSubarrays.push([]);
    for (let end = start + 1; end <= arr.length; end++) {
      allSubarrays[start].push(arr.slice(start, end));
    }
  }
  return allSubarrays;
}

console.log(JSON.stringify(generateSubarrays([1, 8, 9])));

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

(Please note that this organizes the subarrays based on the starting index to flatten the array):

function generateSubarrays(arr) {
  let allSubarrays = [];
  for (let start = 0; start < arr.length; start++) {
    for (let end = start + 1; end <= arr.length; end++) {
      allSubarrays.push(arr.slice(start, end));
    }
  }
  return allSubarrays;
}

console.log(JSON.stringify(generateSubarrays([1, 8, 9])));

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

Answer 6

To convert your reasoning into code, I would suggest using two nested loops.

function generateSubarrays(arr) {
  let allSubarrays = [];
  for (let start = 0; start < arr.length; start++) {
    allSubarrays.push([]);
    for (let end = start + 1; end <= arr.length; end++) {
      allSubarrays[start].push(arr.slice(start, end));
    }
  }
  return allSubarrays;
}

console.log(JSON.stringify(generateSubarrays([1, 8, 9])));

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

(Please note that this organizes the subarrays based on the starting index to flatten the array):

function generateSubarrays(arr) {
  let allSubarrays = [];
  for (let start = 0; start < arr.length; start++) {
    for (let end = start + 1; end <= arr.length; end++) {
      allSubarrays.push(arr.slice(start, end));
    }
  }
  return allSubarrays;
}

console.log(JSON.stringify(generateSubarrays([1, 8, 9])));

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

What is the approach for obtaining the specified arrays using two pointer methodology in JavaScript?

Answer №1

Answer №2

Answer №3

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