What is a more efficient method for verifying the value of an object within an array that is nested within another object in JavaScript?

Is there a more efficient way to check for an object in an array based on a property, without having to go through multiple checks and avoiding potential errors with the ? operator?

/**
 * An API returns a job object like:
 * { id: 123, name: 'The Job', details: [ { detail_name: "Foo", some: "thing" }, { detail_name: "Bar", some: "thing else" } ] }
 */

const fooDetail = job.details.find(attr => {
  return attr.detail_name === 'Foo' });
        
if (fooDetail && fooDetail.detail_name === "Foo") {
  // todo process `some: "thing"` 
}

It can be cumbersome to perform a find operation followed by additional checks to avoid errors. Any suggestions for a better or shorter approach?

Answer №1

Utilize Array.some

If you come across one, it will return true. You can use the same callback as found

const hasDetail = job.details.some(attr => {
  return attr.detail_name === 'Foo' });
        
if (hasDetail) {
  // action to be taken for 'some: "thing"' 
}

If you only wish to retrieve the value and then verify if the property exists later on, you can utilize find along with the ?. operator

const addDetail = job.details.find(attr => {
  return attr.detail_name === 'Foo' });
        
if (addDetail?.detail_name === 'Foo') {
  // action to be taken for 'some: "thing"' 
}

Answer №2

Another option is to

job.details.forEach(item=>{
    if(item.name == "Bar") {
        console.log(item.variable);
    }
});

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