What impact does the //g flag in Regex JavaScript have on the program's state?

I recently had a question that was answered, but I'm still trying to grasp why the regex behaves in a certain way.

According to w3schools, it explains:

g: Perform a global match (find all matches rather than stopping after the first match)

Okay, I understand. That's why the code returns an array like in this example:

var str="The rain in SPAIN stays mainly in the plain";
var patt1=/ain/gi;
document.write(str.match(patt1));

Output:

ain,AIN,ain,ain 

The use of /g in the regex is to replace more than one instance.

However, when looking at the test method:

var re=/hi/gi;
alert(re.test("hi") + " " + re.test("hi"));

The result comes out as "true false".

This inconsistency is puzzling. Why does the behavior change for each call? Shouldn't the global flag work consistently across all calls?

It seems that the lastIndex property is being shared between calls, causing unexpected results. This shared state is not explicitly mentioned and caught me off guard. When would I actually need or want this 'feature'?

Answer №1

Utilizing the global flag in a regex causes the lastIndex property to be updated, indicating the index at which the next match should start.

Visit this link for more information on regular expressions in JavaScript

If needed, you have the option to reset the lastIndex before making another call.

Curious about why using RegExp with global flag in Javascript might yield incorrect results? Check out this discussion

Answer №2

In my opinion, the key issue appears to be using the 'g' modifier instead of the 'm' modifier, which includes '\n' in the list of characters matched by '.'.

If you intend to iterate over specific matches, it's recommended to use the 'g' modifier. You can refer to http://example.com for more information (and look for "Global matching" on that page). Even though this is Perl documentation, there is a useful example provided.

From what I can tell, the Javascript implementation still has flaws since

alert(re.test(new String("hi")) + " " + re.test(new String("xhi")));

produces the outcomes you mentioned. Despite using different objects with different values for the two strings, the index of re should have been reset but seemingly, it remains unchanged.

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