What exactly is the significance of placing a term "in" within a method's parameter list in documentation?

Forgive me for what may seem like a silly question, but I prefer to clarify doubts rather than leave gaps in my knowledge.

Let's look at this snippet taken from developer.mozilla.org:

void initCustomEvent(
    in DOMString type,
    in boolean canBubble,
    in boolean cancelable,
    in any detail
);

From what I understand, there isn't a syntax in JavaScript like void. However, this is just a convention used to indicate that the method does not return anything. (Please correct me if I'm mistaken)

But what exactly does in mean in this context?

Answer №1

When a parameter is identified as an "in-parameter", it means that the value is passed into the function, as opposed to "out-parameters" where the function adds data to the argument or memory location that can be utilized by the calling code.

For instance, the MDN documentation includes an example with an "out-parameter":

void get(
  in string prop,
  in nsIIDRef iid,
  [iid_is(iid),retval] out nsQIResult result
);

Here's a JavaScript sample:

function range(n, result) {
    for (var i = 0; i < n; i++) {
        result.push(i);
    }
}

// Usage
var foo = [];
range(10, foo);
console.log(foo); // displays [0,1,2,3,4,5,6,7,8,9]

While "out-parameters" are uncommon in JavaScript, they are more prevalent in C or C++, the languages in which Firefox is developed.

As suggested by c.P.u1, this syntax is not specific to JavaScript but a representation of the interface. Mozilla utilizes XPIDL. According to their documentation:

Each method parameter can be specified as in, out, or inout. An out parameter functions as an auxiliary return value, though using it in script contexts can be cumbersome. It's recommended to avoid them if possible. An inout parameter is an input parameter whose value may change as a result of the method, and they are generally advised to be avoided if possible due to their complexities.


Indeed, using void signifies that the function does not return anything, but the void operator does have a purpose (unrelated to the interface description).

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