My solution for rendering svgs in three.js involves using the group.scale.y = -1; trick, but it has created an issue with the y coordinate system. When I apply this trick to correct the upside-down svg rendering, the positive y coordinates no longer push the drawing upwards as expected.
This problem raises questions about why the svgs are initially rendered upside down and how to ensure that my y coordinates behave as intended even after applying the scale flip trick.
Did you know that SVGs are rendered upside down in Three.js because of where they are being rendered from?
The X axis in SVGs has positive values drawing further to the right, while the Y axis with positive values draws further down. This calculation is based on the top left point of the image.
In Three.js, it's possible to move left of center (X:0, Y:0) and below center using negative values. In this case, positive Y values move up and negative Y values move down in Three.js canvas.
When the Renderer draws paths/shapes, it uses the original Y value from the SVG which is usually a positive number, causing the drawing coordinate to move up instead of down as in an SVG, resulting in your SVG being rendered upside down.
In the example of utilizing an SVG loader, check out this link for more information: https://github.com/mrdoob/three.js/blob/master/examples/webgl_loader_svg.html
Consider flipping the actual geometry instead of altering the group scale. This approach helps to maintain consistent scale information for the object and/or group.
for ( var j = 0; j < shapes.length; j ++ ) {
var shape = shapes[ j ];
var geometry = new THREE.ShapeBufferGeometry( shape );
geometry.applyMatrix4(new THREE.Matrix4().makeScale ( 1, -1, 1 )) // <-- modified here
var mesh = new THREE.Mesh( geometry, material );
group.add( mesh );
}
One possible remedy involves adjusting the camera perspective to maintain the original geometry and positioning.
camera.up = new THREE.Vector3( 0, 0, -1 );
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