I attempted to replicate the map() method by writing this code in order to double each number in the array. However, I am puzzled as to why the output is 5 without logging it to the console. Moreover, whenever I run the code again, it mysteriously keeps adding 5 to a variable that I never defined?
const numbers = [1, 2, 3, 4, 5];
const doubleNumbers = [];
for (let i = 0; i < numbers.length; i += 1) {
doubleNumbers.push(numbers[i] * 2)
}Explaining why Array.push returns the new length of the array:
let myArray = [];
console.log(myArray.push('example')) // This should show 1
console.log(myArray.push('another example')) // This should display 2If you execute this code in a console, it will automatically print the result of the last statement without any separate logging.
According to the official instructions, using the push() function appends one or multiple items to the array's tail and displays the updated size of the array.
Executing this operation in the console will reveal the final outcome.
https://i.sstatic.net/acQpW.png
The output of your code is satisfactory
const numbers = [1,2,3,4,5];
const doubleNumbers = [];
for (let i = 0; i < numbers.length; i+=1) {
doubleNumbers.push(numbers[i] * 2)
}
console.log(doubleNumbers)
You might want to log the length of the array as well
Are you possibly missing some key information in your explanation? What exactly is the purpose of numbers2? You create a new array called doubleNumbers, but it doesn't seem to be utilized?
doubleNumbers.push(numbers[i] * 2)
I think this solution should function correctly.
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