What could be causing the lack of change in direction for the initial function call?

There appears to be an issue with image(0) and image(1) in this array that I can't quite understand. The console output shows:

i=5; div class="five" id="slides"

i=0; div class="one" id="slides"

i=1; div class="one" id="slides"


Check out my codepen link

var i = 0;
var image = ["one", "two", "three", "four", "five"];
var slider = document.getElementById("slides");
function changeBG(direction) {
  if(direction == "up"){
    if(i != 5) {
        slider.className = image[i];
        console.log(i, slider);
      i++;
    }
    else {
      i = 0;
      slider.className = image[i];
      console.log(i, slider);
      i++;
    }
  }
  else {
    if(i != -1) {
        slider.className = image[i];
        console.log(i, slider);
      i--;
    }
    else {
      i = 4;
      slider.className = image[i];
      console.log(i, slider);
      i--;
    }
  }
  console.log(direction);
}

Update: Upon checking the array, it consists of:

Array [ "one", "two", "three", "four", "five" ]


Further investigation reveals that when switching directions from 'up'' to 'down', the value of i unexpectedly increases instead of decreasing during the first call of changeBG(). Can someone shed some light on this?

Answer №1

It seems like you overlooked something:

elseif {
  num = 1;
  carousel.id = pictures[num];
  num++;//================================> don't forget this part
  console.log(num, carousel);
}

Answer №2

If we assume that the direction is "upward":

In the scenario where i equals 0, you should assign the className to the initial element of the array prior to increasing the value of i. Subsequently, you must display both the className and the newly incremented value of i (where i will be 1 at this juncture).

On the other hand, if i reaches 4, then you ought to reset it back to zero, designate className as the first element in the array, and avoid incrementing

i</code before logging its value - resulting in <code>i
being equal to 0.

Answer №3

In order for the correct output to be displayed, console.log should occur before any increment or decrement of i.

console.log(i, slider);
i++;

Alternatively, you can use console.log(i, image[i]);

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