What could be causing my AJAX code to fail in retrieving information from an API?

Hey everyone, I'm new here and hoping to get some help with an issue I'm facing. I've written a code to fetch data from an API and display it on my HTML page, but for some reason the AJAX code isn't working. There's nothing showing up in the console except for a warning from Chrome:

[Deprecation] Synchronous XMLHttpRequest on the main thread is deprecated because of its detrimental effects to the end user's experience. For more help, check .

Here is the AJAX code I am using, can someone please point out what I might be doing wrong?

$.ajax
({
  type: "GET",
  url: "xxxxxxxxxx",
  dataType: 'json',
  async: false,
  username: "xxxxxxx",
  password: "xxxxxxxxxx",
  data: '{ "id" }',
  success: function (){
    alert('Thanks for your comment!'); 
  }
});

Answer №1

Take a look at the code snippet below for some guidance, and I recommend sticking to the

$.ajax({...})
//Code to run if the request succeeds (is done);
//The response is passed to the function
.done(callback(json))
//Code to run if the request fails; the raw request and
//status codes are passed to the function
.fail(callback(xhr, status, errorThrown))
//Code to run regardless of success or failure;
.always(callback(xhr, status)) 

method as described in the jquery documentation on ajax

$(document).ready(function() {

  $("#btn").click(function(event) {
    var content = $("#content");
    var url = $("#url").val();



    $.ajax({
      type: "GET",
      url: url,
      data:{id:3},//check this line, sending an object instead
      dataType: 'json',
      async: false
    })
    .done(function(data){
      alert('Thanks for your comment!');
      content.text(JSON.stringify(data));//convert object to string
    })
    .fail()
    .always();

  });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">

<p>
  Enter the URL you want to fetch using jQuery's AJAX method
  <input id="url" class="" placeholder="Enter URL" value="https://jsonplaceholder.typicode.com/posts" />
  <button class="btn btn-primary" id="btn">Fetch</button>
</p>

<br>

<div id="content" class="container well">
  Content will be displayed here
</div>

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