Is there a way to determine if an ajax function is occupied by a prior call? What measures can be taken to avoid invoking an ajax function while it is still processing a previous request with a readyState != 4 status?
Is there a way to determine if an ajax function is occupied by a prior call? What measures can be taken to avoid invoking an ajax function while it is still processing a previous request with a readyState != 4 status?
You have the option to utilize a boolean along with a suitable onreadystatechange function;
var inProgress = true;
ajaxRequest = ...
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
inProgress = false;
}
}
Are you considering skipping the Ajax call if the previous one is still in progress? If your preference is to skip it, then Matthew's solution would be ideal for you. However, if you'd rather wait for each call to complete before initiating the next one, a different approach is needed. I can share some code with you if necessary.
I've been developing a potential solution:
<script language="javascript" type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/prototype/1.6.0.3/prototype.js"></script>
<script language="javascript" type="text/javascript">
var requestInProcess = false;
var timer = null;
function requestSomeStuffA() {
var responseHolder = $("responseHolder");
new Ajax.Request(
"http://webservicelocation/",
{
method: 'GET',
contentType: 'application/json; charset=utf-8',
onCreate: function() {
requestInProcess = true;
},
onSuccess: function(transport) {
//handle the response
},
onFailure: function(error) {
//handle errors gracefully
},
onComplete: function() {
requestInProcess = false;
}
}
);
}
function requestSomeStuffB() {
clearTimeout(timer);
if(requestInProcess) {
//wait and retry after a short interval
timer = window.setTimeout("requestSomeStuffB()", 10); //timeout in milliseconds
}
else{
//proceed with the next Ajax request
}
}
</script>
By calling requestSomeStuffA followed by requestSomeStuffB, the latter will wait for the former to finish processing. Hopefully, this solution proves helpful for your situation.
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