Ways to retrieve the final appearance of element m in array n

As a beginner in programming, my goal is to access the last position of element m within array n. The following code displays all positions of element m:

 var n = [];
        while (true) {
            let input = prompt("Please enter a number for the array");
            if (input == null || input == "c") {
                break;
            }
            n.push(Number(input));
            console.log(n);
        }
        var m = prompt("Enter the number to match");
        console.log(m)
        for (var i = 0; i < n.length; i++) {
            if (n[i] == m) {
                console.log(i);
            } 

}

Answer №1

If you want to find the last index of an element in an array, you can utilize the built-in Array.prototype.lastIndexOf() function.

By using the .lastIndexOf() method, you can easily retrieve the last index where a specific element is located within the array. If the element is not found, it will return -1 as an indication. This method conducts a search on the array in reverse order, starting from the last index and moving towards the first index.

n.lastIndexOf(m);

var n = [];
while (true) {
  let input = prompt("enter number to array");
  if (input == null || input == "c") {
    break;
  }
  
  n.push(Number(input));
}

var m = Number(prompt("enter number to be match"));
console.log(n.lastIndexOf(m));

Answer №2

To reverse iterate over the array, you can change up the way the for loop is structured like this:

var n = [];
while (true) {
    let input = prompt("enter number to array");
    if (input == null || input == "c") {
        break;
    }
    n.push(Number(input));
    console.log(n);
}
var m = prompt("enter number to be match");
console.log(m)
for (var i = n.length - 1; i >= 0; i--) {
    if (n[i] == m) {
        console.log(i);
    } 
}

PLEASE NOTE:

While my solution demonstrates how to modify your current approach for the desired outcome, it's worth mentioning that Yousaf's solution offers a more concise and cleaner implementation; if you prefer writing succinct code, consider using their method.

Answer №3

Greetings to the coding community :)

Discovering the index of the last occurrence of an element is a breeze with Array.prototype.lastIndexOf().

It's advisable to handle potential error scenarios, such as non-integer inputs from users. However, for the sake of simplicity, I'll provide the code without error checks.

let numbers = [];

while (true) {
  const input = prompt('Enter a number to add to the array');
  if (!input || input === 'c') {
    break;
  } else {
    numbers.push(Number(input));
    console.log(numbers);
  }
}

const targetNumber = Number(prompt('Enter the number to find'));
console.log(targetNumber);
const lastIndex = numbers.lastIndexOf(targetNumber);
if (lastIndex < 0) {
  console.log(`The element ${targetNumber} could not be found.`);
} else {
  console.log(
    `The last occurrence of ${targetNumber} is at position ${lastIndex}`
  );
}

Answer №4

If you want to find the index of a specific element in an array, you can utilize the n.indexOf(m) function. For more information on how this function works, you can visit this link. Just keep in mind that the index may be negative, indicating that the element is not present in the array.

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