Ways to retrieve all elements based on their class names?

Question

Ways to retrieve all elements based on their class names?

What is the equivalent of using $('.class') in JQuery to get all elements by class name with pure JavaScript?

Answer 1

Answer №1

document.getElementsByClassName(klass)

It is worth noting that some engines, especially older browsers, may not support this method. In such cases, using a shim could be considered. Although it may be slower and iterate over the entire document, it will still function.

UPDATE several years later: A similar result can now be achieved with

document.querySelectorAll('.klass')

. While this may not seem significant, the latter allows for queries on any CSS selector, providing much greater flexibility. This is particularly useful if "get all elements by class name" is just one part of a larger goal, serving as the vanilla JS equivalent to jQuery's $('.class').

Answer 2

document.getElementsByClassName(klass)

It is worth noting that some engines, especially older browsers, may not support this method. In such cases, using a shim could be considered. Although it may be slower and iterate over the entire document, it will still function.

UPDATE several years later: A similar result can now be achieved with

document.querySelectorAll('.klass')

. While this may not seem significant, the latter allows for queries on any CSS selector, providing much greater flexibility. This is particularly useful if "get all elements by class name" is just one part of a larger goal, serving as the vanilla JS equivalent to jQuery's $('.class').

Answer 3

Answer №2

An effortless method to achieve the desired result

let customers = document.getElementsByClassName('custid');
for (let i = 0; i < customers.length; ++i) {
    let element = customers[i];  
    element.innerHTML = 'this is a new value';
}

Answer 4

An effortless method to achieve the desired result

let customers = document.getElementsByClassName('custid');
for (let i = 0; i < customers.length; ++i) {
    let element = customers[i];  
    element.innerHTML = 'this is a new value';
}

Answer 5

Answer №3

var elements = document.querySelectorAll('.your class');

If that doesn't work, you can try creating your own custom classname like this:

if (!document.getElementsByClassName) {
    document.getElementsByClassName=function(className) {
        var allElements=document.getElementsByTagName('*'), matchingElements=[], i=0, element;
        while(element=allElements[i++]) {
            if (element.className == className) {
                matchingElements.push(element);
            }
        }
        return matchingElements;
    }
}

Answer 6

var elements = document.querySelectorAll('.your class');

If that doesn't work, you can try creating your own custom classname like this:

if (!document.getElementsByClassName) {
    document.getElementsByClassName=function(className) {
        var allElements=document.getElementsByTagName('*'), matchingElements=[], i=0, element;
        while(element=allElements[i++]) {
            if (element.className == className) {
                matchingElements.push(element);
            }
        }
        return matchingElements;
    }
}

Answer 7

Answer №4

While some browsers support the document.getElementsByClassName(class) function, others do not. If your browser does not have this feature, you will need to manually check each element in the document to see if it has the desired class name.

Answer 8

While some browsers support the document.getElementsByClassName(class) function, others do not. If your browser does not have this feature, you will need to manually check each element in the document to see if it has the desired class name.

Answer 9

Answer №5

Many different methods were outlined and efficiency tested in this article: http://ejohn.org/blog/getelementsbyclassname-speed-comparison/

Answer 10

Many different methods were outlined and efficiency tested in this article: http://ejohn.org/blog/getelementsbyclassname-speed-comparison/

Answer 11

Answer №6


function findElementsByClass(htmlElement, tagName, className){
    var elements = (tagName == "*" && htmlElement.all)? htmlElement.all :
        htmlElement.getElementsByTagName(tagName);
    var returnElements = new Array();
    className = className.replace(/\-/g, "\\-");
    var regExp = new RegExp("(^|\\s)" + className + "(\\s|$)");
    var element;
    for(var i=0; i<elements.length; i++){
        element = elements[i];     
        if(regExp.test(element.className)){
            returnElements.push(element);
        }   
    }
    return (returnElements)
}

Answer 12


function findElementsByClass(htmlElement, tagName, className){
    var elements = (tagName == "*" && htmlElement.all)? htmlElement.all :
        htmlElement.getElementsByTagName(tagName);
    var returnElements = new Array();
    className = className.replace(/\-/g, "\\-");
    var regExp = new RegExp("(^|\\s)" + className + "(\\s|$)");
    var element;
    for(var i=0; i<elements.length; i++){
        element = elements[i];     
        if(regExp.test(element.className)){
            returnElements.push(element);
        }   
    }
    return (returnElements)
}

Answer 13

Answer №7

Here is a simple solution:

function findElementsByClassName(className)
{
    var foundElements = [];
    var allTags = document.getElementsByTagName("*");

    for(var i = 0; i < allTags.length; i++)
    {
        if(allTags[i].className == className)
        {
            foundElements.push(allTags[i]);
        }
    }

    return foundElements;
}

Answer 14

Here is a simple solution:

function findElementsByClassName(className)
{
    var foundElements = [];
    var allTags = document.getElementsByTagName("*");

    for(var i = 0; i < allTags.length; i++)
    {
        if(allTags[i].className == className)
        {
            foundElements.push(allTags[i]);
        }
    }

    return foundElements;
}

Ways to retrieve all elements based on their class names?

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

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