Ways to organize by worth and exclusively display items exceeding a specific value?

Question

Ways to organize by worth and exclusively display items exceeding a specific value?

I am looking to organize an array of objects by filtering out items based on a value returned from a function, and then only return the objects' items that exceed a certain threshold.

Here is my attempt at achieving this:

sortedObject(){
  return this.arrayOfObjects.sort((a, b) =>
    (this.formatValue(b) > 0.7) - (this.formatValue(a) > 0.7)
  )
}

The function this.formatValue takes an item and calculates a value between 0 and 1 based on its properties. I want to sort and filter the items such that only those with a value above 0.7 are included in the sortedObject computed property. Any item with a value below 0.7 will not be part of the sorted result.

javascript vue.js ecmascript-6

Answer 1

Answer №1

When it comes to sorting, it's more than just arranging things. First, you have to filter out items with a value less than 0.7 before sorting the remaining ones:

My approach would be to map the computed values first, then filter and finally sort them:

sortedObject(){
  return this.arrayOfObjects.map(a => this.formatValue(a))
                            .filter(a => a > 0.7)
                            .sort((a, b) => b - a)
}

Edit

sortedObject(){
  return this.arrayOfObjects.filter(a => this.formatValue(a) > 0.7)
                            .sort(
                              (a, b) =>
                                this.formatValue(b) - this.formatValue(a)
                            )
}

Answer 2

When it comes to sorting, it's more than just arranging things. First, you have to filter out items with a value less than 0.7 before sorting the remaining ones:

My approach would be to map the computed values first, then filter and finally sort them:

sortedObject(){
  return this.arrayOfObjects.map(a => this.formatValue(a))
                            .filter(a => a > 0.7)
                            .sort((a, b) => b - a)
}

Edit

sortedObject(){
  return this.arrayOfObjects.filter(a => this.formatValue(a) > 0.7)
                            .sort(
                              (a, b) =>
                                this.formatValue(b) - this.formatValue(a)
                            )
}

Answer 3

Answer №2

sort function will return an array of the same length as the original array, meaning you can't accomplish this in a single call. One option is to first use filter before calling sort.

sortedObject() {
  return this.arrayOfObjects
             .filter(a => this.formatValue(a) > 0.7)
             .sort((a, b) => this.formatValue(b) - this.formatValue(a))
}

If the formatValue() function is resource-intensive and you want to only call it once per object, you can map it to a new Array before using filter. However, this will result in an array of objects with an additional property formatValue

sortedObject() {
  return this.arrayOfObjects
    .map(a => ({ formatValue: this.formatValue(a), ...a}))
    .filter(a => a.formatValue > 0.7)
    .sort((a, b) => b.formatValue - a.formatValue)
}

Alternatively, you can opt to include a getter property within each object and invoke the formatValue() function through it.

Answer 4

sort function will return an array of the same length as the original array, meaning you can't accomplish this in a single call. One option is to first use filter before calling sort.

sortedObject() {
  return this.arrayOfObjects
             .filter(a => this.formatValue(a) > 0.7)
             .sort((a, b) => this.formatValue(b) - this.formatValue(a))
}

If the formatValue() function is resource-intensive and you want to only call it once per object, you can map it to a new Array before using filter. However, this will result in an array of objects with an additional property formatValue

sortedObject() {
  return this.arrayOfObjects
    .map(a => ({ formatValue: this.formatValue(a), ...a}))
    .filter(a => a.formatValue > 0.7)
    .sort((a, b) => b.formatValue - a.formatValue)
}

Alternatively, you can opt to include a getter property within each object and invoke the formatValue() function through it.

Answer 5

Answer №3

Implementing a user filter pipe in this code snippet, the function filters and sorts an array of objects based on a specific condition. For more information on the Array.filter method, you can visit this link.

sortedObject(){
  return this.arrayOfObjects
..filter(a=> a > 0.7);
.sort((a, b) =>
    (this.formatValue(b) > 0.7) - (this.formatValue(a) > 0.7)
  )
}

Answer 6

Implementing a user filter pipe in this code snippet, the function filters and sorts an array of objects based on a specific condition. For more information on the Array.filter method, you can visit this link.

sortedObject(){
  return this.arrayOfObjects
..filter(a=> a > 0.7);
.sort((a, b) =>
    (this.formatValue(b) > 0.7) - (this.formatValue(a) > 0.7)
  )
}

Ways to organize by worth and exclusively display items exceeding a specific value?

Answer №1

Edit

Answer №2

Answer №3

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