I am working with two arrays:
const arr1 = ["apple","banana"];
const arr2 = ["x","y","z"];
Is there a way to achieve the desired output below?
apple x, apple y, apple z, banana x, banana y, banana z
I am working with two arrays:
const arr1 = ["apple","banana"];
const arr2 = ["x","y","z"];
Is there a way to achieve the desired output below?
apple x, apple y, apple z, banana x, banana y, banana z
let arr1 = ["one", "two"];
let arr2 = ["apple", "banana", "cherry"];
const resultArray = [];
arr1.forEach(elem1 => {
arr2.forEach(elem2 => {
resultArray.push(elem1 + " " + elem2)
})
})
console.log(resultArray);Check out this unique approach utilizing Array.prototype.flatMap() and Array.prototype.map():
const array1 = ["aaa","bbb"];
const array2 = ["f1","f2","f3"];
const result = array1.flatMap(v1 => array2.map(v2 => `${v1} ${v2}`));
console.log(result);const fruits = ["apple", "banana"];
const colors = ["red","blue","yellow"];
let combinations=[];
fruits.forEach( fruit => {
colors.forEach( color => {
combinations.push( fruit +' '+ color );
})
});
console.log( combinations );
'use strict';
let firstArray = ["apple", "banana"];
let secondArray = ["red", "yellow", "green"];
let result = [];
firstArray.forEach( fruit => secondArray.forEach(color => result.push([`${fruit} ${color}`])) );
const words1 = ["red","blue"];
const words2 = ["car","bike","bus"];
let combinedWords = []
for (w1 of words1) {
for (w2 of words2) {
combinedWords.push(w1 + ' ' + w2);
}
}
To achieve the desired outcome, you can utilize the reduce() and map() functions in conjunction with the Spread syntax.
Feel free to refer to the code snippet provided below:
let array1 = ["apple", "banana"],
array2 = ["red", "green", "yellow"];
let result = array1.reduce((acc, val) => [...acc, array2.map(item => `${val} ${item}`).join(',')], []);
console.log(result.join(','));
Using Loop
let fruits = ["apple","banana"];
let colors = ["red","blue","green"];
let combinations = [];
let count=0;
for(let i=0;i<fruits.length;i++) {
for(let j=0;j<colors.length;j++) {
combinations[count] = `${fruits[i]} ${colors[j]}`;
count++;
}
}
console.log(combinations);
Using For Each
fruits.forEach(fruit => {
colors.forEach(color => {
tempNewArray.push(fruit + " " + color)
})
})
console.log(tempNewArray);
JSFiddle Fiddle
To achieve this, utilize the power of Array.prototype.reduce() in conjunction with Array.prototype.map(), spread syntax, and template literals.
Here is a sample code snippet:
const arr1 = ["apple", "banana"];
const arr2 = ["red", "yellow"];
const resultArr = arr1.reduce((acc, curr) => [...acc, ...arr2.map(color => `${curr} ${color}`)], []);
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