Ways to evaluate negative numbers in JavaScript

I need to validate latitude and longitude values within the range of -180 to 180. If a number falls outside of this range, an error should be displayed.

Below is the code I have written for this validation:

 
if((markerPoint[0] && parseInt(markerPoint[0],10) < -180 || parseInt(markerPoint[0],10) > 180)) {
        this.latlngError.push("Invalid coordinates");
    } else {
        this.isLanLngValid = true;
    }

However, it seems that the comparison is not working correctly.

Answer №1

I need to validate values within the range of -180 to 180.

When checking for numbers between -180 and 180, they should be greater than -180 and less than 180. Therefore, we need to adjust the comparison.

if(dataPoint[0] && parseInt(dataPoint[0],10) > -180 && parseInt(dataPoint[0],10) < 180) {

Answer №2

Check out this JsFiddle link

let num = prompt("Enter a number");
checkNumber();
function checkNumber() {
  if (num >= -180 && num <= 180) {
    alert("Success! We did it!");
  } else {
    num = prompt("Invalid, please try again");
    checkNumber();
  }
}

Answer №3

Please use the following code snippet which is guaranteed to work.
if(markerPoint[0]>=-180 && markerPoint[0]<=180)

Answer №4

A common issue with the given code is the precedence of logical operators in JavaScript, where && takes priority over ||. This means that the logic is interpreted as if it were enclosed in parentheses:

if (
    (markerPoint[0] && parseInt(markerPoint[0],10) < -180)
    ||
    parseInt(markerPoint[0],10) > 180)
{

To correct this, you can use parentheses to explicitly define the order of operations:

if(markerPoint[0] && (parseInt(markerPoint[0],10) < -180 || parseInt(markerPoint[0],10) > 180)) {

By doing so, the if condition will be met if markerPoint[0] has a non-false value and falls outside the range [-180, 180].

Answer №5

Consider utilizing the Math.abs() function like this:

if (markerPoint[0] && Math.abs(parseInt(markerPoint[0],10)) > 180)

Update: @TedHopp pointed out a potential issue with operator precedence in your current code. Remember that && has higher precedence than ||. A way to avoid this problem is by using Math.abs().

If the problem persists, consider providing more code for further assistance.

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