Ways to efficiently insert a single element into an array multiple times simultaneously

Can you please help me improve my function that displays the number of coins corresponding to a certain value? For example, an input of 56 should return [25, 25, 5, 1].

I am facing two challenges: 1) How can I display multiple instances of the same coin in the array (I suspect there may be an issue with the Math function below)? 2) Is it possible to remove any 0s from the array?

Any assistance would be greatly appreciated.

function getCoins(){
    let coins = [25, 10, 5, 1];
    amount = prompt("Enter an amount to convert into coins");
    coinAmount = "";

    for (i = 0; i < coins.length; i++){
        if (amount % coins[i] >= 0){ 
            coinAmount += coins[i] * (Math.floor(amount/coins[i])) + ",";
            amount = amount % coins[i];  
            console.log(coinAmount)
        } 
    }
}

getCoins()

javascriptarrays

Answer №1

To display the array, you can utilize the push method and then use join.

If you want to combine coinAmount with a new Array(NumberOfCouns) using concat, consider filling it with the corresponding coin type using fill.

A function named getCoins is created for converting an amount into coins. The coins array contains values [25, 10, 5, 1]. The user inputs an amount which is processed into coins. Each iteration checks if there are enough coins to create the desired amount. If so, it adds them to coinAmount using concat and fill methods.

Answer №2

What do you think of this approach?

function calculateChange(){
    let coins = [25, 10, 5, 1];
        amount = prompt ("Please enter an amount to convert into change");
        coinAmount = "";


    for (i = 0; i < coins.length; i++){
        if (amount >= coins[i]){ 
            var quantity = parseInt(amount/coins[i]);
            coinAmount +=  quantity + ","; 
            amount -= quantity*coins[i];     
            console.log (coinAmount);
        }
        else{
            coinAmount += "0,";
            console.log (coinAmount);
        }
    } 
}

calculateChange()

For input of 30:

1,
1,0,
1,0,1,
1,0,1,0,

The output indicates we have one coin worth 25 and one coin worth 5

For an input of 25:

1,
1,0,
1,0,0,
1,0,0,0,

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