Waiting for camera access in JavaScript: How to ensure proper execution before proceeding?

Question

Waiting for camera access in JavaScript: How to ensure proper execution before proceeding?

Below is the code I am using from Twilio to access the local camera on the browser :

async function ShowLocalVideo() {   
    Twilio.Video.createLocalVideoTrack().then(track => {
        const localMediaContainer = document.getElementById('LocalMedia');
        localMediaContainer.appendChild(track.attach());        
      });
}

I want to ensure that the user has granted access to the camera before proceeding with other steps. Ideally, I would like to wait for their response. This is why I am calling:

await ShowLocalVideo();
alert('Hi !');

However, the alert Hi ! pops up before the browser prompt asking for camera access.

Is there a way to pause the execution of the code until the user responds to This file wants to use your camera. ?

javascript twilio

Answer 1

Answer №1

By combining the async/await syntax with using Promise .then, you might be encountering some issues. If you fail to await on the result of

createLocalVideoTrack().then(...)

, the async function could return prematurely. To address this, consider replacing .then with await in the following manner:

async function DisplayLocalVideo() {   
    const track = await Twilio.Video.createLocalVideoTrack();
    const localMediaContainer = document.getElementById('LocalMedia');
    localMediaContainer.appendChild(track.attach());        
}

Alternatively, you have the option to await the outcome of

createLocalVideoTrack().then(...)

, but this approach may introduce mixed styles and cause confusion.

Answer 2

By combining the async/await syntax with using Promise .then, you might be encountering some issues. If you fail to await on the result of

createLocalVideoTrack().then(...)

, the async function could return prematurely. To address this, consider replacing .then with await in the following manner:

async function DisplayLocalVideo() {   
    const track = await Twilio.Video.createLocalVideoTrack();
    const localMediaContainer = document.getElementById('LocalMedia');
    localMediaContainer.appendChild(track.attach());        
}

Alternatively, you have the option to await the outcome of

createLocalVideoTrack().then(...)

, but this approach may introduce mixed styles and cause confusion.

Waiting for camera access in JavaScript: How to ensure proper execution before proceeding?

Answer №1

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