Vue.js Conditional RoutingIn Vue.js, conditional routing allows

Question

Vue.js Conditional RoutingIn Vue.js, conditional routing allows

I'm currently facing a challenge where I want to display two different views for the same path based on the presence of a token in LocalStorage. While I could easily handle this logic within each view itself, I'm exploring the possibility of achieving this directly in the Router.

Here's an example:

export default new Router({
  mode: "history",
  base: process.env.BASE_URL,
  routes: [
    {
      path: "/",
      name: "home",
      component: function() {
        if (...) {
          return ViewA
        } else {
          return ViewB
        }
      }
    },
  ]
});

I've attempted the above code but unfortunately, it didn't work as expected. The application builds without error, but neither of the two views is being displayed.

javascript vue.js single-page-application vue-router

Answer 1

Answer №1

To handle this situation, the use of a getter would be appropriate, ensuring that both components are imported:

import ViewA from '@/views/ViewA'
import ViewB from '@/views/ViewB'

export default new Router({
    mode: "history",
    base: process.env.BASE_URL,
    routes: [
        {
            path: "/",
            name: "home",
            get component() {
                if (...) {
                    return ViewA;
                } else {
                    return ViewB;
                }
            }
        },
    ]
});

In my personal notes, I've made a remark stating "cannot find documentation on this" in relation to the above code snippet. While not directly related, you may find it beneficial to explore information from concerning the render function. By adapting the discussion there to your specific scenario provided above.

component: {
    render(c) {
        if (...) {
            return c(ViewA);
        } else {
            return c(ViewB);
        }
    }
}

Answer 2

To handle this situation, the use of a getter would be appropriate, ensuring that both components are imported:

import ViewA from '@/views/ViewA'
import ViewB from '@/views/ViewB'

export default new Router({
    mode: "history",
    base: process.env.BASE_URL,
    routes: [
        {
            path: "/",
            name: "home",
            get component() {
                if (...) {
                    return ViewA;
                } else {
                    return ViewB;
                }
            }
        },
    ]
});

In my personal notes, I've made a remark stating "cannot find documentation on this" in relation to the above code snippet. While not directly related, you may find it beneficial to explore information from concerning the render function. By adapting the discussion there to your specific scenario provided above.

component: {
    render(c) {
        if (...) {
            return c(ViewA);
        } else {
            return c(ViewB);
        }
    }
}

Answer 3

Answer №2

After some experimentation, I discovered a straightforward approach to achieve this by leveraging the webpack lazy loading feature in vue router alongside a vuex store state property.

{
  path: '/',
  component: () => { 
    if (store.state.domain) {
      return import(/* webpackChunkName: "app-home" */ '../views/AppHome.vue');
    } else {
      return import(/* webpackChunkName: "home" */ '../views/Home.vue');
    }
  }
},

By implementing the code above, I was able to dynamically import my home component and determine the route component based on the value of the domain property within my vuex store. It is important to ensure that you have properly set up your vuex store and imported it into your router for this method to function correctly.

The original solution provided in the inquiry would have been successful if the component was returned as an import.

Answer 4

After some experimentation, I discovered a straightforward approach to achieve this by leveraging the webpack lazy loading feature in vue router alongside a vuex store state property.

{
  path: '/',
  component: () => { 
    if (store.state.domain) {
      return import(/* webpackChunkName: "app-home" */ '../views/AppHome.vue');
    } else {
      return import(/* webpackChunkName: "home" */ '../views/Home.vue');
    }
  }
},

By implementing the code above, I was able to dynamically import my home component and determine the route component based on the value of the domain property within my vuex store. It is important to ensure that you have properly set up your vuex store and imported it into your router for this method to function correctly.

The original solution provided in the inquiry would have been successful if the component was returned as an import.

Answer 5

Answer №3

I previously addressed a similar question and my response can be found here.

Below is an illustration:

routes: [
    {
      path: '*',
      beforeEnter(to, from, next) {
        let components = {
          default: [X, Y, Z][Math.floor(Math.random() * 100) % 3],
        };
        to.matched[0].components = components;

        next();
      }
    },

... where X, Y, Z represent components that are randomly selected each time the route changes. For your scenario, you have the flexibility to customize the beforeEnter logic as per your requirements and assign any desired component before routing to it.

Answer 6

I previously addressed a similar question and my response can be found here.

Below is an illustration:

routes: [
    {
      path: '*',
      beforeEnter(to, from, next) {
        let components = {
          default: [X, Y, Z][Math.floor(Math.random() * 100) % 3],
        };
        to.matched[0].components = components;

        next();
      }
    },

... where X, Y, Z represent components that are randomly selected each time the route changes. For your scenario, you have the flexibility to customize the beforeEnter logic as per your requirements and assign any desired component before routing to it.

Vue.js Conditional RoutingIn Vue.js, conditional routing allows

Answer №1

Answer №2

Answer №3

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