Verify whether the elements of an array satisfy a condition only when they are adjacent in a JavaScript program

Question

Verify whether the elements of an array satisfy a condition only when they are adjacent in a JavaScript program

Consider the following array :

[500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5]

My goal is to extract all values less than 350 that are contiguous. Here is the desired result :

[[250], [250, 230, 100], [200, 100, 10], [5]]

This is what I have tried so far:

const result = []
array.forEach((item, index, arr) => {
     if (item <= 350 && arr[index + 1] <= 350) {
          brokenMeasurements.push(item)
     }
})

I am struggling with identifying when the contiguous values end. Currently, this code only retrieves all values under 350.

javascript arrays

Answer 1

Answer №1

To extract values from an array that are less than or equal to 350, you can iterate through the array and store these values in a temporary array. Once a value greater than 350 is encountered, the temporary array is pushed into the final result (if it contains more than one value) and then cleared. At the end of the iteration, if there are still values remaining in the temporary array, they are also added to the final result:

array = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5]

const result = []
var values = []
const l = array.length
for (let i = 0; i < l; i++) {
  v = array[i]
  if (v <= 350) {
    values.push(v)
  } else if (values.length) {
    if (values.length > 1) result.push(values);
    values = [];
  }
}
if (values.length > 1) result.push(values);

console.log(result)
// [[250, 230, 100], [200, 100, 10]]

Note that this code specifically adds sequences of values under 350 with more than one element to the final result. If you wish to include all sequences regardless of length, modify the condition:

values.length > 1

to simply

values.length

array = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5]

const result = []
var values = []
const l = array.length
for (let i = 0; i < l; i++) {
  v = array[i]
  if (v <= 350) {
    values.push(v)
  } else if (values.length) {
    result.push(values);
    values = [];
  }
}
if (values.length) result.push(values);

console.log(result)
// [[250], [250, 230, 100], [200, 100, 10], [5]]

Answer 2

To extract values from an array that are less than or equal to 350, you can iterate through the array and store these values in a temporary array. Once a value greater than 350 is encountered, the temporary array is pushed into the final result (if it contains more than one value) and then cleared. At the end of the iteration, if there are still values remaining in the temporary array, they are also added to the final result:

array = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5]

const result = []
var values = []
const l = array.length
for (let i = 0; i < l; i++) {
  v = array[i]
  if (v <= 350) {
    values.push(v)
  } else if (values.length) {
    if (values.length > 1) result.push(values);
    values = [];
  }
}
if (values.length > 1) result.push(values);

console.log(result)
// [[250, 230, 100], [200, 100, 10]]

Note that this code specifically adds sequences of values under 350 with more than one element to the final result. If you wish to include all sequences regardless of length, modify the condition:

values.length > 1

to simply

values.length

array = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5]

const result = []
var values = []
const l = array.length
for (let i = 0; i < l; i++) {
  v = array[i]
  if (v <= 350) {
    values.push(v)
  } else if (values.length) {
    result.push(values);
    values = [];
  }
}
if (values.length) result.push(values);

console.log(result)
// [[250], [250, 230, 100], [200, 100, 10], [5]]

Answer 3

Answer №2

var numbers = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5];
var output = [];
numbers.reduce((prev, current, index) => {
    if (current <= 350) {
        prev.push(current);
        if (index === numbers.length - 1) output.push(prev);
    }
    else {
        if (prev.length >= 1) output.push(prev);
        prev = [];
    }
    return prev;
}, []);
console.log(output)

Answer 4

var numbers = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800, 5];
var output = [];
numbers.reduce((prev, current, index) => {
    if (current <= 350) {
        prev.push(current);
        if (index === numbers.length - 1) output.push(prev);
    }
    else {
        if (prev.length >= 1) output.push(prev);
        prev = [];
    }
    return prev;
}, []);
console.log(output)

Answer 5

Answer №3

Here is a code snippet you can experiment with:

const numbers = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800]
let tempArray = []
const lessThan350 = numbers.reduce((result, num) => {
  if(num < 350) {
    tempArray.push(num)
  } else {
    result.push(tempArray)
    tempArray = []
  }
  return result
}, []).filter(element => element.length > 1)
console.log(lessThan350)

Answer 6

Here is a code snippet you can experiment with:

const numbers = [500, 250, 380, 250, 230, 100, 700, 900, 200, 100, 10, 800]
let tempArray = []
const lessThan350 = numbers.reduce((result, num) => {
  if(num < 350) {
    tempArray.push(num)
  } else {
    result.push(tempArray)
    tempArray = []
  }
  return result
}, []).filter(element => element.length > 1)
console.log(lessThan350)

Verify whether the elements of an array satisfy a condition only when they are adjacent in a JavaScript program

Answer №1

Answer №2

Answer №3

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