I am struggling with extracting numbers from a string that may contain numbers and converting them into a comma-separated value.
var stringOne = "Returned 12 string";
var extractNum = "1,2"
After successfully extracting the numbers, I need to check if any of them are greater than 1 using a regular expression. But despite trying different approaches, I haven't been able to make it work. Any suggestions on how to achieve this would be greatly appreciated! Thanks in advance!
Looking to verify whether your extracted string contains numbers larger than 1? Give this code snippet a try:
function validateNumbers() {
var str = "1,1,1,1,2,1,1";
var pattern = new RegExp("[2-9]");
return pattern.test(str); // returns true
}
let numbers = "12 string to be returned".match(/[2-9]/g)
if (numbers !== null) {
alert(numbers.join(','));
} else {
// No matching numbers found
}Below is a possible solution:
let nums = "1,2";
let hasGreaterThan1 = nums.split(',').some(function(num) { return num > 1; })
For more information, refer to the Array.prototype.some documentation.
It would be best to parse the number and utilize the built-in numerical operators in JavaScript for this task.
If you absolutely feel the need to accomplish it with a regular expression, one approach could be: ^[2-9]|\d{2,}$. This pattern will verify if the number is either a single digit between 2 and 9 or a multi-digit number.
If there is any number greater than 1, the variable "ok" will be set to true.
const stringOne = "Returned 12 string";
const extractNums = "1,2";
let ok = checkIfGreaterThanOne(extractNums);
function checkIfGreaterThanOne(str){
const numsArray = str.split(",");
for(let i=0; i<numsArray.length; i++){
let num = parseInt(numsArray[i]);
if(num > 1){
return true;
}
}
return false;
}
Avoid regular expressions entirely
let numbers = extractNum.split(',').map(function(num){return parseInt(num) > 1})
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