Utilizing Regular Expressions in JavaScript to substitute a group of characters with nothing

Need assistance creating a regular expression to remove specific characters from a string. Here is the list of characters to be removed:

public static char[] delimiters = { ' ', '\r', '\n', '?', '!', ';', '.', ',', '`', ':', '(', ')', '{', '}', '[', ']', '|', '\'', '\\', '~', '=', '@', '>', '<', '&', '%', '-', '/', '#' };

Answer №1

let input = "...";
let output = input.replace(/[ \r\n?!:;\-(){}\[\]\\'"=@><&%\/#]+/g, '');

It is possible that I overlooked a few characters.

Instead of using a blacklist approach, another option is to use a whitelist:

let output = input.replace(/[^\w]+/g, '');

This will eliminate anything that isn't considered a word character, such as letters (uppercase or lowercase), digits, or underscores.

Answer №2

Here is the regular expression you need to use:

var re = /[ \r\n?!;.,`:(){}\[\]\|\'\\~=@><&%-\/#]/g;

For instance:

var test = "j a\nv\ra?s!c;r.i,p`t:I(s)A{w}e[s]o|m'e\\~=@><&%-/#";
test.replace(re, '')

>>> "javascriptIsAwesome"

Just so you know, the usual format for this type of expression in regular expressions is "/[...]/" - which means, "match any character within the brackets"

Answer №3

Give this a shot:

const delimiters = [' ', '\r', '\n', '?', '!', ';', '.', ',', '`', ':', '(', ')', '{', '}', '[', ']', '|', '\'', '\\', '~', '=', '@', '>', '<', '&', '%', '-', '/', '#'],
    regex = new RegExp("[" + delimiters.join("").replace(/[-\\\]]/g, "\\$&") + "]", "g");
str = str.replace(regex, "");

Answer №4

To handle this situation, you can create a custom function that will escape any special characters in a regular expression, then apply the regex and return the modified string:

String.prototype.escapeChars = function(specialChars) {
    for(var i=0; i<specialChars.length; i++) {
        if(specialChars[i].match(/\W/)) {
            specialChars[i] = '\\'+specialChars[i];
        }
    }
    return this.replace(new RegExp('['+specialChars.join('')+']', 'g'), '');
};

var inputString = "j a\nv\ra?s!c;r.i,p`t:I(s)A{w}e[s]o|m'e\\~=@><&%-/#"; 

inputString.escapeChars([' ', '\r', '\n', '?', '!', ';', '.', ',', '`', ':', '(', ')', '{', '}', '[', ']', '|', '\'', '\\', '~', '=', '@', '>', '<', '&', '%', '-', '/', '#']);

// result: "JavascriptIsAwesome"

Answer №5

This seems a bit intense.

/[^A-z0-9]/g

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