Utilizing regex to eliminate irregular spaces and achieve an equal number of spaces in a character array

Question

Utilizing regex to eliminate irregular spaces and achieve an equal number of spaces in a character array

How can I implement this functionality in JavaScript? The concept involves checking the number of spaces that appear after a specific pattern in a character array. If the number of spaces is odd, one space should be removed to make it even. If the number of spaces is already even, they should remain unchanged.

For example:

* abc \n * abc

In the above case, there are 3 spaces between \n and *, so the desired output would have 2 spaces between \n and *

* abc \n * abc

The pattern being referred to here is the spaces that occur between * and \n.

javascript regex

Answer 1

Answer №1

If you want to achieve a similar result, try the following method:

let str = "* abc  \n   * abc";
console.log(str.replace(/((  )+) ?/g, "$1"));

The pattern "(( )+)" captures even numbers of spaces, while " ?" captures any optional space that may follow. Subsequently, "$1" is used to replace all instances of spaces with the captured even number of spaces.

Answer 2

If you want to achieve a similar result, try the following method:

let str = "* abc  \n   * abc";
console.log(str.replace(/((  )+) ?/g, "$1"));

The pattern "(( )+)" captures even numbers of spaces, while " ?" captures any optional space that may follow. Subsequently, "$1" is used to replace all instances of spaces with the captured even number of spaces.

Utilizing regex to eliminate irregular spaces and achieve an equal number of spaces in a character array

Answer №1

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