Currently, I am utilizing the lodash uniqWith method to eliminate duplicate items with the same id from my array.
However, the lodash method retains the first duplicated item, whereas I actually want to keep the last duplicated item.
Is there a way to achieve this?
var result = _.uniqWith(editedData, function(arrVal, othVal) {
return arrVal.id === othVal.id;
});
console.log(result)
To implement a uniqueByLast function utilizing the _.flow() method, you can employ _.keyBy() to create an object based on 'id', and then use _.values() to convert it into an array:
const { flow, partialRight: pr, keyBy, values } = _
const lastUniqBy = iteratee => flow(
pr(keyBy, iteratee),
values
)
const arr = [{ id: 1, val: 1 }, { id: 1, val: 2 }, { id: 2, val: 1 }, { id: 2, val: 2 }]
const result = lastUniqBy('id')(arr)
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.js"></script>Similarly, you can achieve the same functionality using lodash/fp:
const { flow, keyBy, values } = _
const lastUniqBy = iteratee => flow(
keyBy(iteratee),
values
)
const arr = [{ id: 1, val: 1 }, { id: 1, val: 2 }, { id: 2, val: 1 }, { id: 2, val: 2 }]
const result = lastUniqBy('id')(arr)
console.log(result)<script src='https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js)'></script>The simplest method? Start by reversing the array (make sure to clone it first to prevent any changes).
var output = _.uniqWith(_.reverse(_.clone(editedData)), function(arrayValue, otherValue) {...});
You could also streamline your code like this:
var output = _.uniqWith(_.reverse(_.clone(editedData)), ({ id: x }, { id: y }) => x === y);
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