Utilizing ES6 array methods to convert multidimensional arrays into chart-ready data

Question

Utilizing ES6 array methods to convert multidimensional arrays into chart-ready data

Seeking help with converting an array to a specific data format for chart display.

The chrart.js library requires data in the following format:

dataset = [ { label: 'one', data: []}, 
           {label: 'two', data: []}
        ];

I receive response data in another format, which is in random order and needs to be appropriately changed with the respective labels.

Here is the code and trial I have attempted:

const dataset = [
    {
        detail: {
            team: [
                { name: 'alpha', game: 1 },
                { name: 'beta', game: 1 },
                { name: 'gamma', game: 1 },
                { name: 'delta', game: 1 },
                { name: 'echo', game: 1 }
            ]
        }
    },
    // more data objects here...
];

const teams = dataset.map(ds => ds.detail.team);
let z = teams.map(element => {
    return element.map(e => {
        let p = {};
        let n = e.name;
        let c = e.game;
        p[n] = c;
        return p;
    });
});

console.log('z', z);

let nt = [];

z.reduce((c, n, i, a) => {
    let z1 = n.map(i => {
        console.log(i);
        let entries = Object.entries(i);
        return entries.map(e => {
          return { label: e[0], data: e[1] };
        });
    });
    return z1;
}, [])

Desired output:

[
    {
        label: 'alpha',
        data: [1, 2, 0, 0, 2, 0]
    },
    // more formatted data objects...
]

I am struggling with the array.reduce method to achieve the desired output. Any ES6 solution suggestions would be greatly appreciated.

If you can provide any insights or assistance, it would be highly valued. Thank you!

javascript arrays ecmascript-6

Answer 1

Answer №1

Let's keep your dataset as is and build up from scratch to achieve the desired output.

First step: de-nest the data:

dataset.map(d => d.detail.team)

Next, consolidate all teams into a single array:

dataset
  .map(object => object.detail.team)
  .reduce((acc, team) => acc.concat(team))

Now that we have a unified list of names and games, let's transform this into a hash:

dataset
  .map(object => object.detail.team)
  .reduce((acc, team) => acc.concat(team))
  .reduce((acc, team) =>{
    acc[team.name] = acc[team.name] || []
    acc[team.name].push(team.game)
    return acc
  }, {})

We now possess a hash mapping names to games. By using Object.entries on this hash, we can obtain label pairs:

Object.entries(
  dataset
    .map(object => object.detail.team)
    .reduce((acc, team) => acc.concat(team))
    .reduce((acc, team) =>{
      acc[team.name] = acc[team.name] || []
      acc[team.name].push(team.game)
      return acc
    }, {})
)

Finally, we can iterate over these pairs to formulate the final object:

Object.entries(
  dataset
    .map(object => object.detail.team)
    .reduce((acc, team) => acc.concat(team), [])
    .reduce((acc, team) =>{
      acc[team.name] = acc[team.name] || []
      acc[team.name].push(team.game)
      return acc
    }, {})
)
  .map(([team, games]) => ({ team, games }))

The challenge lies in consolidating these steps together efficiently.

Surprisingly, most steps can be combined! Simply loop over each object, manually reference the structure, iterate through individual team arrays, and construct our hash.

Object.entries(
  dataset
    .reduce((acc, object) =>{
      object.detail.team.forEach(team =>{
        acc[team.name] = acc[team.name] || []
        acc[team.name].push(team.game)
      })
      return acc
    }, {})
)
  .map(([team, games]) => ({ team, games }))

Additional Details

Introduction to Arrow Functions

In our example, arrow functions were utilized to embrace ES6 standards, fulfilling the request for modern syntax usage. For more insights on arrow functions, refer to the MDN documentation. Essentially, they offer a concise way to define functions:

function test(value){ return console.log(value) }
// equivalent to
let test = value => console.log(value)

function add(a, b){ return a + b)
// equivalent to
let add = (a,b) => a + b

Exploring `Array.prototype.forEach()`

In our streamlined approach, we leveraged Array.prototype.forEach() to modify the accumulator without explicit returns. Unlike methods designed for returning values, forEach excels at facilitating side effects quickly, perfect for our scenario where tweaking the accumulator shape is paramount.

Diving Into Destructuring Arrays

Introducing destructuring - a handy feature allowing retrieval of values from predictable object or array structures. For a comprehensive overview, visit the MDN guide. Here's a snippet showcasing its power:

var a, b, rest;
[a, b] = [10, 20];
console.log(a); // 10
console.log(b); // 20

[a, b, ...rest] = [10, 20, 30, 40, 50];
console.log(a); // 10
console.log(b); // 20
console.log(rest); // [30, 40, 50]

({ a, b } = { a: 10, b: 20 });
console.log(a); // 10
console.log(b); // 20

Answer 2

Let's keep your dataset as is and build up from scratch to achieve the desired output.

First step: de-nest the data:

dataset.map(d => d.detail.team)

Next, consolidate all teams into a single array:

dataset
  .map(object => object.detail.team)
  .reduce((acc, team) => acc.concat(team))

Now that we have a unified list of names and games, let's transform this into a hash:

dataset
  .map(object => object.detail.team)
  .reduce((acc, team) => acc.concat(team))
  .reduce((acc, team) =>{
    acc[team.name] = acc[team.name] || []
    acc[team.name].push(team.game)
    return acc
  }, {})

We now possess a hash mapping names to games. By using Object.entries on this hash, we can obtain label pairs:

Object.entries(
  dataset
    .map(object => object.detail.team)
    .reduce((acc, team) => acc.concat(team))
    .reduce((acc, team) =>{
      acc[team.name] = acc[team.name] || []
      acc[team.name].push(team.game)
      return acc
    }, {})
)

Finally, we can iterate over these pairs to formulate the final object:

Object.entries(
  dataset
    .map(object => object.detail.team)
    .reduce((acc, team) => acc.concat(team), [])
    .reduce((acc, team) =>{
      acc[team.name] = acc[team.name] || []
      acc[team.name].push(team.game)
      return acc
    }, {})
)
  .map(([team, games]) => ({ team, games }))

The challenge lies in consolidating these steps together efficiently.

Surprisingly, most steps can be combined! Simply loop over each object, manually reference the structure, iterate through individual team arrays, and construct our hash.

Object.entries(
  dataset
    .reduce((acc, object) =>{
      object.detail.team.forEach(team =>{
        acc[team.name] = acc[team.name] || []
        acc[team.name].push(team.game)
      })
      return acc
    }, {})
)
  .map(([team, games]) => ({ team, games }))

Additional Details

Introduction to Arrow Functions

In our example, arrow functions were utilized to embrace ES6 standards, fulfilling the request for modern syntax usage. For more insights on arrow functions, refer to the MDN documentation. Essentially, they offer a concise way to define functions:

function test(value){ return console.log(value) }
// equivalent to
let test = value => console.log(value)

function add(a, b){ return a + b)
// equivalent to
let add = (a,b) => a + b

Exploring `Array.prototype.forEach()`

In our streamlined approach, we leveraged Array.prototype.forEach() to modify the accumulator without explicit returns. Unlike methods designed for returning values, forEach excels at facilitating side effects quickly, perfect for our scenario where tweaking the accumulator shape is paramount.

Diving Into Destructuring Arrays

Introducing destructuring - a handy feature allowing retrieval of values from predictable object or array structures. For a comprehensive overview, visit the MDN guide. Here's a snippet showcasing its power:

var a, b, rest;
[a, b] = [10, 20];
console.log(a); // 10
console.log(b); // 20

[a, b, ...rest] = [10, 20, 30, 40, 50];
console.log(a); // 10
console.log(b); // 20
console.log(rest); // [30, 40, 50]

({ a, b } = { a: 10, b: 20 });
console.log(a); // 10
console.log(b); // 20

Answer 3

Answer №2

To achieve the desired output, one can utilize the Array.reduce() method to create a map and then use that map accordingly.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
var map = dataset.reduce((a,curr)=>{
    curr.detail.team.forEach((e)=> (a[e.name]= (a[e.name] || [])).push(e.game));
    return a;
}, {});
var result =[];

Object.keys(map).forEach((key)=>{
  result.push({
    "label" : key,
    "data" : map[key]
  });
});

console.log(result);

Answer 4

To achieve the desired output, one can utilize the Array.reduce() method to create a map and then use that map accordingly.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
var map = dataset.reduce((a,curr)=>{
    curr.detail.team.forEach((e)=> (a[e.name]= (a[e.name] || [])).push(e.game));
    return a;
}, {});
var result =[];

Object.keys(map).forEach((key)=>{
  result.push({
    "label" : key,
    "data" : map[key]
  });
});

console.log(result);

Answer 5

Answer №3

One approach is to utilize the reduce method to transform an array into a flat structure, followed by iterating over it to achieve the desired output format.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
const flat = dataset.reduce( (a,b) => a.concat(b.detail.team), []);
let result = [];

for (let element of flat) {

  let match = null;

  for (let e  of result) {
    if (e.label === element.name) {
      match = e;
    }
  }

  if (match) {
    match.data.push(element.game)
  }
  else {
    result.push({
      label : element.name,
      data  : [element.game]
    });
  }

}

console.log(result);

Answer 6

One approach is to utilize the reduce method to transform an array into a flat structure, followed by iterating over it to achieve the desired output format.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
const flat = dataset.reduce( (a,b) => a.concat(b.detail.team), []);
let result = [];

for (let element of flat) {

  let match = null;

  for (let e  of result) {
    if (e.label === element.name) {
      match = e;
    }
  }

  if (match) {
    match.data.push(element.game)
  }
  else {
    result.push({
      label : element.name,
      data  : [element.game]
    });
  }

}

console.log(result);

Answer 7

Answer №4

Try this alternative approach: iterate through the data set as is and save the outcomes in a dictionary-like object called map, while also storing them in the result array to be returned.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
var result = [],
  map = {};
dataset.forEach(a => {
  a.detail.team.forEach(b => {
    if (!(b.name in map)) {
      map[b.name] = [];
      result.push({
        'label': b.name,
        'data': map[b.name]
      })
    }
    map[b.name].push(b.game);
  });
});
console.log(result);

Avoid using reduce or map functions on arrays in this scenario.

Answer 8

Try this alternative approach: iterate through the data set as is and save the outcomes in a dictionary-like object called map, while also storing them in the result array to be returned.

const dataset = [{detail:{team:[{name:'alpha',game:1},{name:'beta',game:1},{name:'gamma',game:1},{name:'delta',game:1},{name:'echo',game:1}]}},{detail:{team:[{name:'alpha',game:2},{name:'beta',game:2},{name:'echo',game:2},{name:'gamma',game:2},{name:'delta',game:2}]}},{detail:{team:[{name:'echo',game:1},{name:'delta',game:0},{name:'beta',game:0},{name:'gamma',game:0},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'beta',game:0},{name:'gamma',game:1},{name:'alpha',game:0}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:0},{name:'alpha',game:2},{name:'gamma',game:3},{name:'beta',game:2}]}},{detail:{team:[{name:'delta',game:0},{name:'echo',game:1},{name:'beta',game:0},{name:'gamma',game:2},{name:'alpha',game:0}]}}];
var result = [],
  map = {};
dataset.forEach(a => {
  a.detail.team.forEach(b => {
    if (!(b.name in map)) {
      map[b.name] = [];
      result.push({
        'label': b.name,
        'data': map[b.name]
      })
    }
    map[b.name].push(b.game);
  });
});
console.log(result);

Avoid using reduce or map functions on arrays in this scenario.

Utilizing ES6 array methods to convert multidimensional arrays into chart-ready data

Answer №1

Additional Details

Introduction to Arrow Functions

Exploring `Array.prototype.forEach()`

Diving Into Destructuring Arrays

Answer №2

Answer №3

Answer №4

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