Utilize the power of checkboxes in Vue.js and Quasar framework to enable specific functionalities upon being

There are two checkboxes available: 'Show Active' and 'Show Live'. Initially, the 'Show Live' checkbox is disabled.

I need a feature where if 'Show Active' is checked, it will enable the 'Show Live' checkbox. And if 'Show Active' is unchecked, the 'Show Live' checkbox should be unchecked and disabled as well.

Below is the code snippet for reference:

<div id="q-app">
<q-checkbox left-label v-model="searchForm.active" label="Show Active"></q-checkbox>
  <q-checkbox left-label v-model="searchForm.live" label="Show Live"></q-checkbox>
</div>

<script>
const {
  useQuasar
} = Quasar
const {
  ref,
  onMounted,
  reactive
} = Vue

const app = Vue.createApp({
  setup() {
    const $q = useQuasar()

    const searchForm = reactive({
      active: false,
      live: false
    });

    function notify() {
      $q.notify('Running on Quasar v' + $q.version)
    }

   

    return {
      notify,
      searchForm
    }
  }
})

app.use(Quasar, {
  config: {}
})
app.mount('#q-app')

</script>

https://jsfiddle.net/ubjsf2zv/10/

I am just beginning to learn vue.js and quasar framework

Answer №1

To resolve this issue, I suggest using the props disable with a condition.

I have created an example on https://jsfiddle.net/jLxg3q7m/

Simply implement the following code:

<q-checkbox :disable="searchForm.active === false && (searchForm.live = false)" left-label v-model="searchForm.live" label="Show Live"></q-checkbox>

By adding this code snippet

:disable="searchForm.active === false && (searchForm.live = false)"
:

  • The first condition searchForm.active === false will disable it if active is false.
  • The second part (searchForm.live = false) will set live to false.

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