Utilize Regular Expressions to validate phone numbers

Question

Utilize Regular Expressions to validate phone numbers

Currently tackling a Regex challenge.

let phones = ['321-1234567','+355 321 1234567','0103 1234500', '00 355 3211234567' ]

Desired results:

3211234567
+3553211234567
+3551031234500
+3553211234567

Implemented solution:

phones.forEach(phone => {
      phone = phone.replace(/^0+/,'+355').replace(/[^+\d]+/g, '')
      console.log(phone)
    })

Output:

3211234567
+3553211234567
+3551031234500
+3553553211234567 --->incorrect , supposed to be: +3553211234567

The current implementation only works for the first three elements in the array, failing to handle the last case where two zeros need replacing with + when starting with 00.

To address this,

How can I achieve this using Regex, or should I resort to conditional statements like if phone.startsWith()?

This question offers unique circumstances compared to other solutions available online.

javascript regex

Answer 1

Answer №1

Transforming phone numbers in an array using JavaScript:

let phones = ['321-1234567','+355 321 1234567','0103 1234500', '00 355 3211234567' ]

phones = phones.map(r => r
  .replace(/^00/,'+')
  .replace(/^0/,'+355')
  .replace(/[^+\d]+/g, '')
)

console.log(phones)

Answer 2

Transforming phone numbers in an array using JavaScript:

let phones = ['321-1234567','+355 321 1234567','0103 1234500', '00 355 3211234567' ]

phones = phones.map(r => r
  .replace(/^00/,'+')
  .replace(/^0/,'+355')
  .replace(/[^+\d]+/g, '')
)

console.log(phones)

Answer 3

Answer №2

If you need to manipulate phone numbers, here's a useful code snippet:

let phones = ['321-1234567','+355 321 1234567','0103 1234500', '00 355 3211234567' ]
for (const phone of phones) {
  console.log(
      phone.replace(/^0{1,2}/, (x) => x=='00'?'+':'+355')
           .replace(/(?!^\+)\D/g, ''))
}

Insights:

```
.replace(/^0{1,2}/, (x) => x=='00'?'+':'+355')
```
- This regex pattern matches either '00' or '0' at the beginning of the string and replaces it with either '+' or '+355'. The ternary operator is used for conditional replacement.
.replace(/(?!^\+)\D/g, '') eliminates any non-digit characters except '+' if it appears at the start of the string.

Regex breakdown:

^0{1,2} - ^ marks the beginning of the string and 0{1,2} matches one or two occurrences of zero.
(?!^\+)\D - (?!^\+) acts as a negative lookahead that rejects the match if the character immediately following is '+' at the string's start. \D matches any non-digit character.

Answer 4

If you need to manipulate phone numbers, here's a useful code snippet:

let phones = ['321-1234567','+355 321 1234567','0103 1234500', '00 355 3211234567' ]
for (const phone of phones) {
  console.log(
      phone.replace(/^0{1,2}/, (x) => x=='00'?'+':'+355')
           .replace(/(?!^\+)\D/g, ''))
}

Insights:

```
.replace(/^0{1,2}/, (x) => x=='00'?'+':'+355')
```
- This regex pattern matches either '00' or '0' at the beginning of the string and replaces it with either '+' or '+355'. The ternary operator is used for conditional replacement.
.replace(/(?!^\+)\D/g, '') eliminates any non-digit characters except '+' if it appears at the start of the string.

Regex breakdown:

^0{1,2} - ^ marks the beginning of the string and 0{1,2} matches one or two occurrences of zero.
(?!^\+)\D - (?!^\+) acts as a negative lookahead that rejects the match if the character immediately following is '+' at the string's start. \D matches any non-digit character.

Answer 5

Answer №3

The issue lies in this specific line of code replace(/^0+/,'+355'). You should modify it to be replace(/^0+/,'+')

phones.forEach(phone => {
      phone = phone.replace(/^0+/,'+').replace(/[^+\d]+/g, '')
      console.log(phone)
    })

Answer 6

The issue lies in this specific line of code replace(/^0+/,'+355'). You should modify it to be replace(/^0+/,'+')

phones.forEach(phone => {
      phone = phone.replace(/^0+/,'+').replace(/[^+\d]+/g, '')
      console.log(phone)
    })

Utilize Regular Expressions to validate phone numbers

Answer №1

Answer №2

Answer №3

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