Utilize Express to Refine HTTP Responses

Question

Utilize Express to Refine HTTP Responses

I am currently in the process of developing a polls application using express. The structure of my data is as follows:

var responseSchema = new mongoose.Schema({
    responseText: String,
    voters: []

})
module.exports = mongoose.model('Responses', responseSchema);

var pollsSchema = new mongoose.Schema({
    question: String,
    responses: [responseSchema],
})

When handling routes, I extract the ID from the parameters and generate an object that contains relevant information for the specific poll. However, this object includes a 'voters' array which stores SessionID's of users who have voted for each response. It is not ideal for this array to be included in the response.

My goal is to send back all details except for the 'voters' array. Is there a way to filter the http response so that it only contains the necessary data?

javascript json angularjs http express

Answer 1

Answer №1

If you have a data structure containing an array called voters and you wish to eliminate this array, you can achieve this by using delete obj.voters to remove the property from the object.

For example, if your object looks like this:

var obj = {
    someField: someValue,
    someOtherField: someOtherValue,
    voters: [...]
}

You can delete the voters property like so:

delete obj.voters;

Just a heads up, if you are converting this database result into JSON for an Express route, another method would be to build a new object specifically for the HTTP response and only include the properties you want from the database query result object. This approach involves creating a deliberate representation of the response object instead of simply mirroring what is in your database. By doing this, any additions to the database fields will not automatically appear in the JSON returned from your route unless you intentionally update your route. Essentially, the route will only return the fields that you chose to include, rather than everything in the database query result by default.

Answer 2

If you have a data structure containing an array called voters and you wish to eliminate this array, you can achieve this by using delete obj.voters to remove the property from the object.

For example, if your object looks like this:

var obj = {
    someField: someValue,
    someOtherField: someOtherValue,
    voters: [...]
}

You can delete the voters property like so:

delete obj.voters;

Just a heads up, if you are converting this database result into JSON for an Express route, another method would be to build a new object specifically for the HTTP response and only include the properties you want from the database query result object. This approach involves creating a deliberate representation of the response object instead of simply mirroring what is in your database. By doing this, any additions to the database fields will not automatically appear in the JSON returned from your route unless you intentionally update your route. Essentially, the route will only return the fields that you chose to include, rather than everything in the database query result by default.

Utilize Express to Refine HTTP Responses

Answer №1

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