Utilize AJAX to dynamically insert data into the database

Question

Utilize AJAX to dynamically insert data into the database

I have created a JSP page that displays records, and now I am looking to include a dynamic link or button in the JSP that allows inserting data into the database without needing to refresh the page.

This link should open a pop-up window with input fields and a submit button where I can add new entries to the database. After submitting, I want the page to redirect back to the same JSP without any refreshing.

Any advice or resources you can provide would be greatly appreciated as this concept is new to me.

Thank you!

java javascript ajax jsp

Answer 1

Answer №1

If you're looking to submit a form from the client side to your controller, here is a simple example of how you can do it using jQuery AJAX.

$.ajax({
    dataType: "json",
    method: "POST",
    url: 'publicProcurements/' + publicProcurementId + '/selectCandidates/informCandidacies/saveInformCandidacies.do',
    data: $('#informCandidaciesForm').serialize(),
    success: function (data) {
        //You can implement any desired logic here, such as closing a dialog
    }
});

As for the backend logic of saving this form in the database through the controller, it would involve more extensive code that I can't provide in this response. Our goal here is to answer questions and guide you, but not write entire code solutions.

Answer 2

If you're looking to submit a form from the client side to your controller, here is a simple example of how you can do it using jQuery AJAX.

$.ajax({
    dataType: "json",
    method: "POST",
    url: 'publicProcurements/' + publicProcurementId + '/selectCandidates/informCandidacies/saveInformCandidacies.do',
    data: $('#informCandidaciesForm').serialize(),
    success: function (data) {
        //You can implement any desired logic here, such as closing a dialog
    }
});

As for the backend logic of saving this form in the database through the controller, it would involve more extensive code that I can't provide in this response. Our goal here is to answer questions and guide you, but not write entire code solutions.

Answer 3

Answer №2

To begin, create a click function for this purpose.

$('#id_button').click(function(){
        // Retrieve necessary parameters using jQuery .val method
          var param1 = $('#param1').val();
        //alert(s_id);
        $.post('../servlet_name',{param1:param1},function(msg) {

 });

Then, in your servlet retrieve the parameter with request.getParameter("param1") and handle the insertion here.

Next, send a response back to the AJAX indicating completion, such as a flag.

PrintWriter writer = response.getWriter();
writer.println("1");

Returning to the AJAX function now, the value will be received as 'msg'. In this case, 'msg' will be equal to 1 as sent from the servlet.

Subsequently, you can notify the user that data has been successfully inserted.

$.post('../servlet_name', {param1: param1}, function(msg) {
        if (msg == "1") {
          alert("Data added");
        }
     });

I trust this guidance is helpful.

Answer 4

To begin, create a click function for this purpose.

$('#id_button').click(function(){
        // Retrieve necessary parameters using jQuery .val method
          var param1 = $('#param1').val();
        //alert(s_id);
        $.post('../servlet_name',{param1:param1},function(msg) {

 });

Then, in your servlet retrieve the parameter with request.getParameter("param1") and handle the insertion here.

Next, send a response back to the AJAX indicating completion, such as a flag.

PrintWriter writer = response.getWriter();
writer.println("1");

Returning to the AJAX function now, the value will be received as 'msg'. In this case, 'msg' will be equal to 1 as sent from the servlet.

Subsequently, you can notify the user that data has been successfully inserted.

$.post('../servlet_name', {param1: param1}, function(msg) {
        if (msg == "1") {
          alert("Data added");
        }
     });

I trust this guidance is helpful.

Answer 5

Answer №3

To determine the answer, consider your specific needs and desires.

Incorporate a link or button into your HTML file:

<a href='' id='insertButton'>Insert</a>

Implement this ajax script (ensure jQuery plugin is included first):

$("#insertButton").click(function(event){

    var request = $.ajax({

        type: "POST", //default is GET
        url: "controller/action", //customize with your method URL
        data: {} //pass parameters here (e.g., data:{name: 'John', age: 45}) 

    });
    request.done(response){
        console.log("Response:");
        console.log(response);
        yourCallbackFunction(response); //Update view with the response
    }
    request.fail(error){
        console.log("Error:");
        console.log(error);
    }

    return false; //prevent user redirection from input's submit behavior.

});

For real-time synchronization between your View (html) and database, explore Angular JS and Firebase.

Answer 6

To determine the answer, consider your specific needs and desires.

Incorporate a link or button into your HTML file:

<a href='' id='insertButton'>Insert</a>

Implement this ajax script (ensure jQuery plugin is included first):

$("#insertButton").click(function(event){

    var request = $.ajax({

        type: "POST", //default is GET
        url: "controller/action", //customize with your method URL
        data: {} //pass parameters here (e.g., data:{name: 'John', age: 45}) 

    });
    request.done(response){
        console.log("Response:");
        console.log(response);
        yourCallbackFunction(response); //Update view with the response
    }
    request.fail(error){
        console.log("Error:");
        console.log(error);
    }

    return false; //prevent user redirection from input's submit behavior.

});

For real-time synchronization between your View (html) and database, explore Angular JS and Firebase.

Utilize AJAX to dynamically insert data into the database

Answer №1

Answer №2

Answer №3

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