set = [500,1000,1500,2000];
for (var j = 0; j < 4; j++) {
setTimeout(console.log('Hi'), set[j]);}
What could be causing this code not to display 'Hi' after the specified intervals in the list?
set = [500,1000,1500,2000];
for (var j = 0; j < 4; j++) {
setTimeout(console.log('Hi'), set[j]);}
What could be causing this code not to display 'Hi' after the specified intervals in the list?
Here is the correct approach:
arr = [500,1000,1500,2000];
for (var index = 0; index < 4; index++) {
setTimeout(function(){console.log('Greetings')}, arr[index]);
}
This method is preferred because setTimeout requires a callback function instead of a direct statement.
The console.log() function is being called immediately and its return value is passed as an argument to the setTimeout function.
Instead of passing a return value, it is recommended to pass a function. You can achieve this by using the bind() method which will create a new function that invokes log with the appropriate context and specified arguments.
setTimeout(console.log.bind(console, 'Hello'), numberList[index]);
Check out this code snippet
arr = [10, 20, 30, 40];
for (var j = 0; j <= arr.length; j++) {
(function(ind) {
setTimeout(function() { console.log(ind); }, j * arr[j]);
})(j);
}
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