Using regular expressions and the `replace()` method to swap out elements in an array with

Question

Using regular expressions and the `replace()` method to swap out elements in an array with

I'm still getting the hang of JavaScript and I'm attempting to update array elements using regex that match specific strings. Below is a snippet of code I've been working on:

<button onclick="myFunction()">Click Here</button>
<p id="demo"></p>
<script>
function myFunction() {
    var abc = ["deno", "eno","pqr","lenovo"];
    var i, text = "";
    for(i = 0; i < abc.length; i++) {
        text += abc[i].replace(/no/i, "po");
        document.getElementById("demo").innerHTML = text;
    }
}
</script>

My goal is to replace any array element containing "no" with "po."

This is what I am aiming for:

abc["depo","epo","pqr","lepovo"]

javascript arrays regex str-replace

Answer 1

Answer №1

For each individual item, you have the option to do the following:

for(var j=0; j < def.length; j++) {
    def[j] = def[j].replace('no', 'po');
}

Alternatively, you can use a single line like this:

def = def.map(function(y){return y.replace('no', 'po');});

Or opt for a more concise approach using "arrow functions":

def = def.map(y => y.replace('no', 'po'));

Once you have made changes to the array, you can convert it into a string with the help of:

var text = 'def['; 

for ( var j = 0 ; j < def.length ; j++ ) {
    text+='\"'+def[j]+'\"';
    if ( j != def.length - 1) {
        text+=',';
    }
}
text += ']';

Test:

function yourFunction() {
    var def = ["hello", "world","python","lenovo"];
    def = def.map(y => y.replace('o', 'e')); // explore other options mentioned above

    var text = 'def['; 

    for ( var j = 0 ; j < def.length ; j++ ) {
        text+='\"'+def[j]+'\"';
        if ( j != def.length - 1) {
            text+=',';
        }
    }
    text += ']';
    document.getElementById("example").innerHTML = text;
}

<button onclick="yourFunction()">ClickHere</button>
<p id="example"></p>

Answer 2

For each individual item, you have the option to do the following:

for(var j=0; j < def.length; j++) {
    def[j] = def[j].replace('no', 'po');
}

Alternatively, you can use a single line like this:

def = def.map(function(y){return y.replace('no', 'po');});

Or opt for a more concise approach using "arrow functions":

def = def.map(y => y.replace('no', 'po'));

Once you have made changes to the array, you can convert it into a string with the help of:

var text = 'def['; 

for ( var j = 0 ; j < def.length ; j++ ) {
    text+='\"'+def[j]+'\"';
    if ( j != def.length - 1) {
        text+=',';
    }
}
text += ']';

Test:

function yourFunction() {
    var def = ["hello", "world","python","lenovo"];
    def = def.map(y => y.replace('o', 'e')); // explore other options mentioned above

    var text = 'def['; 

    for ( var j = 0 ; j < def.length ; j++ ) {
        text+='\"'+def[j]+'\"';
        if ( j != def.length - 1) {
            text+=',';
        }
    }
    text += ']';
    document.getElementById("example").innerHTML = text;
}

<button onclick="yourFunction()">ClickHere</button>
<p id="example"></p>

Answer 3

Answer №2

let index, result;
for(index = 0; index < letters.length, index++) {
  result += letters[index].replace("yes", "good");
}
console.log(result);

Answer 4

let index, result;
for(index = 0; index < letters.length, index++) {
  result += letters[index].replace("yes", "good");
}
console.log(result);

Answer 5

Answer №3

To make your code function correctly, you need to implement three modifications:

Initialize the text variable with an empty string as it is not set by default.
Update the reference from abc[i].length to abc.length so that the loop iterates properly.

After the line abc[i].length in the for loop, replace the comma with a semicolon.

var abc = ["deno", "eno","pqr","lenovo"];
var i;
var text = "";
for(i = 0; i < abc.length; i++) {
   text += abc[i].replace("no", "po");
}

Answer 6

To make your code function correctly, you need to implement three modifications:

Initialize the text variable with an empty string as it is not set by default.
Update the reference from abc[i].length to abc.length so that the loop iterates properly.

After the line abc[i].length in the for loop, replace the comma with a semicolon.

var abc = ["deno", "eno","pqr","lenovo"];
var i;
var text = "";
for(i = 0; i < abc.length; i++) {
   text += abc[i].replace("no", "po");
}

Using regular expressions and the `replace()` method to swap out elements in an array with

Answer №1

Test:

Answer №2

Answer №3

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