How can I arrange 4 numbers in ascending order using only if-else and else-if statements in JavaScript without utilizing the sort function?
How can I arrange 4 numbers in ascending order using only if-else and else-if statements in JavaScript without utilizing the sort function?
Using only if and else statements (along with assignment operations or a way to switch elements), sorting can be achieved by manually comparing each pair of elements.
Below is an example pseudo-code demonstrating this process for three elements:
if element[0] > element[1]: # swap 0/1 if necessary
temp = element[1]
element[1] = element[0]
element[0] = temp
if element[1] > element[2]: # swap 1/2 if necessary
temp = element[2]
element[2] = element[1]
element[1] = temp
if element[0] > element[1]: # swap 0/1 if necessary
temp = element[1]
element[1] = element[0]
element[0] = temp
As the number of elements increases, this manual comparison approach becomes more complex, leading to multiple comparisons as shown in the following comments:
# swap 0/1 if needed
# swap 1/2 if needed
# swap 2/3 if needed
# swap 0/1 if needed
# swap 1/2 if needed
# swap 0/1 if needed
For larger datasets, utilizing loops or built-in sort functions would be more efficient than continuing with this laborious manual sorting method.
let numbers = [7, 4, 6, 3];
function swapNumbers(arr, index1, index2) {
let temp = arr[index1];
arr[index1] = arr[index2];
arr[index2] = temp;
}
if (numbers[0] > numbers[3]) {
swapNumbers(numbers, 0, 3);
}
if (numbers[1] > numbers[3]) {
swapNumbers(numbers, 1, 3);
}
if (numbers[2] > numbers[3]) {
swapNumbers(numbers, 2, 3);
}
if (numbers[0] > numbers[2]) {
swapNumbers(numbers, 0, 2);
}
if (numbers[1] > numbers[2]) {
swapNumbers(numbers, 1, 2);
}
if (numbers[0] > numbers[1]) {
swapNumbers(numbers, 0, 1);
}
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