Using an arbitrary object as an argument in a CoffeeScript anonymous function

Question

When I execute the below Coffeescript code:

@total = (a, b) -> a + b

The resulting compiled Javascript is:

(function() {

    this.total = function(a, b) {
        return a + b;
    };

}).call(this);

Is there a method in Coffeescript to substitute this with a different object, such as exampleObject or something else in .call(this)?

Answer 1

Answer №1

When you compile the CoffeeScript code, the lines <code>(function() {

and }).call(this); are automatically added by the executable, not from compiling @sum = .... See the actual compiled result here:

this.sum = function(x, y) {
  return x + y;
};

If you want to customize the output, you can run coffee -b -c (or coffee -bc or coffee --bare --compile) with the following code:

(-> 
  @sum = (x, y) -> x + y
).call WHATEVER

will be transformed into

(function() {
  return this.sum = function(x, y) {
    return x + y;
  };
}).call(WHATEVER);

Answer 2

When you compile the CoffeeScript code, the lines <code>(function() {

and }).call(this); are automatically added by the executable, not from compiling @sum = .... See the actual compiled result here:

this.sum = function(x, y) {
  return x + y;
};

If you want to customize the output, you can run coffee -b -c (or coffee -bc or coffee --bare --compile) with the following code:

(-> 
  @sum = (x, y) -> x + y
).call WHATEVER

will be transformed into

(function() {
  return this.sum = function(x, y) {
    return x + y;
  };
}).call(WHATEVER);

Answer 3

calculate.add = (num1, num2) -> num1 + num2

To compile it properly (Note: Check out Rob W's recommendation for compilation settings), do the following:

calculate.add = function(num1, num2) {
  return num1 + num2;
};

Does this meet your requirements? You can then use calculate.add x, y

The complete code is as follows:

calculate = {}
calculate.add = (num1, num2) -> num1 + num2

alert(calculate.add 8, 6)

Answer 4

calculate.add = (num1, num2) -> num1 + num2

To compile it properly (Note: Check out Rob W's recommendation for compilation settings), do the following:

calculate.add = function(num1, num2) {
  return num1 + num2;
};

Does this meet your requirements? You can then use calculate.add x, y

The complete code is as follows:

calculate = {}
calculate.add = (num1, num2) -> num1 + num2

alert(calculate.add 8, 6)