Using a regular expression to divide a string while ensuring that double tokens are avoided

Question

Using a regular expression to divide a string while ensuring that double tokens are avoided

When splitting a string into an array using JavaScript, delimiters play a crucial role. If there are repeated delimiters, it indicates sub-values within the array. For example:

abc+!+;def+!+!+;123+!+;xyz

should be split into abc, [def, 123], xyz.

I've tried numerous variations and ended up with ((?:+!(?!+!))+\;|$), which may have been my initial attempt. After spending a lot of time on this, I seem to have hit a roadblock. I looked into resources like regex to parse string with escaped characters, but couldn't find a solution that fits my specific issue.

I'm sure someone out there is more knowledgeable in regular expressions than I am and I hope they can provide a solution.

javascript arrays regex string split

Answer 1

Answer №1

After experimenting with different methods, I managed to achieve success by utilizing the .split() function along with a specific pattern found in this reference:

\b\+!\+;\b

Following that initial step, I proceeded to implement the following:

\b\+!\+!\+;\b

This process was repeated as needed. To fully automate this procedure, it is advisable to convert it into a recursive function. If you require assistance in creating one, I have constructed a basic JSFiddle to help get you started. Firstly, we divide the string using our original expression. Subsequently, we modify the expression by appending !\+ (this can be achieved dynamically). Consequently, we iterate through the initial array, check for matches with the new expression, and if found, further split the string.

var string = 'abc+!+;def+!+!+;123+!+;xyz',
    data = string.split(/\b\+!\+;\b/);

var regex = /\b\+!\+!\+;\b/
for(var i = 0; i < data.length; i++) {
    var string = data[i];

    if(string.match(regex)) {
        data[i] = string.split(regex);
    }
}

console.log(data);
// ["abc", ["def", "123"], "xyz"]

The implementation of transforming this into a recursive function has been left to the discretion of OP. Should you require additional guidance in this matter, feel free to reach out for more detailed explanations.

Answer 2

After experimenting with different methods, I managed to achieve success by utilizing the .split() function along with a specific pattern found in this reference:

\b\+!\+;\b

Following that initial step, I proceeded to implement the following:

\b\+!\+!\+;\b

This process was repeated as needed. To fully automate this procedure, it is advisable to convert it into a recursive function. If you require assistance in creating one, I have constructed a basic JSFiddle to help get you started. Firstly, we divide the string using our original expression. Subsequently, we modify the expression by appending !\+ (this can be achieved dynamically). Consequently, we iterate through the initial array, check for matches with the new expression, and if found, further split the string.

var string = 'abc+!+;def+!+!+;123+!+;xyz',
    data = string.split(/\b\+!\+;\b/);

var regex = /\b\+!\+!\+;\b/
for(var i = 0; i < data.length; i++) {
    var string = data[i];

    if(string.match(regex)) {
        data[i] = string.split(regex);
    }
}

console.log(data);
// ["abc", ["def", "123"], "xyz"]

The implementation of transforming this into a recursive function has been left to the discretion of OP. Should you require additional guidance in this matter, feel free to reach out for more detailed explanations.

Using a regular expression to divide a string while ensuring that double tokens are avoided

Answer №1

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Using a regular expression to divide a string while ensuring that double tokens are avoided

Answer №1

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