Use the filter method to organize arrays into subarrays based on their length, filtering out those with a length greater than or

Hey there, I've been working on incorporating the array filter property to separate subarrays that are greater than and less than 3 into two distinct functions. Unfortunately, I'm a bit stuck on how to continue fixing my functions. Can someone provide assistance and also explain why I'm currently getting unexpected results?

var subarrays = [
    [1,2,3],
    ['a','b','c','d','e'],
    ['hippopatamus', 'zebra', 'crocodile','lion'],
    [false, 2]
];

var greaterThan3 = function(array){ 
    for(var i = 0; i < array.length; i ++){
        if(array[i].length > 3) {
            return array[i];
        } else {
            return false;
        }
    }
};

var lessThan3 = function(array){
    var arr = [];
    for(var i = 0; i < array.length; i ++){
        if(array[i].length < 3){
            arr.push(array[i]);
        } else {
            return false;
        }
    }
    return arr;
};

After running the greater than function, only the animal names appear. It appears that the "length" parameter is referencing the length of words in the arrays rather than the length of the entire array itself. How can I target the length of the whole array instead? When using the less than function, I'm only getting single letters returned. Once again, my goal is to focus on the length of the array as a whole, not just its contents. Any help would be greatly appreciated. Thank you!

Answer №1

If you're wondering why all you're getting are animals, it's probably because the greater than function isn't being applied to a separate array. Instead, it's always returning the last sub-array, which happens to be the one with animals.

Here is an example of some subarrays: [[1,2,3], ['a','b','c','d','e'], ['hippopatamus', 'zebra', 'crocodile','lion'], [false, 2]];

You can iterate over these subarrays using the forEach function:

var greaterArray = [];

subarrays.forEach(function(subArray){

if(subArray.length>3)
{
greaterArray.push(subArray);
}
});

Alternatively,

You can also use the filter method for a cleaner solution:

subArrays.filter(function(subArray)
{
return subArray.length>3;
});

The filter method creates a new array internally based on whether the values are truthy or falsy, and returns this new array.

Answer №3

I'm currently working on incorporating the array filter property

If you are considering adding a function to the prototype, here's how you can do it:

Filtering arrays for items greater than and less than 3

You can utilize the `forEach` method to iterate over each element in the array and check their length.

 var subarrays = [[1,2,3], ['a','b','c','d','e'], ['hippopatamus', 'zebra', 'crocodile','lion'], [false, 2]];
Array.prototype.sub3 = function(array){
var _newArray=[];
subarrays.forEach(function(item){
   if(item.length !==3){
 _newArray.push(item)
}
})
return _newArray
}
console.log(subarrays.sub3())

View JSFIDDLE example

Answer №4

Is this similar to what you're looking for?

let groups = [[4, 5, 6], ['x', 'y', 'z'], ['elephant', 'giraffe', 'zebra', 'monkey']]; 

const lessThan4 = (arr) => {
   return arr.filter((a) => {
     return a.length < 4;
   });
};

const moreThan4 = (arr) => {
   return arr.filter((a) => {
     return a.length > 4;
   });
};

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