Presenting the question:
checkPassword([["Peter", "P"], ["Sarah", "S"], ["Ethan", "R"]], {"Peter": "P", "Sarah": "Q", //"Ethan":"E"})
Presenting the question:
checkPassword([["Peter", "P"], ["Sarah", "S"], ["Ethan", "R"]], {"Peter": "P", "Sarah": "Q", //"Ethan":"E"})
Are you attempting to manipulate an object like an array and compare array to object as values?
To achieve this, you should treat the object as an object and compare the values within. I recommend using the following code for this task;
function findMismatchedPasswords(attempts, credentials) {
// Initialize an empty array
let mismatchedPasswords = [];
// Iterate through the object, extracting key-value pairs
for (const [key, value] of Object.entries(credentials)) {
// Iterate through the attempts array
for (var i = 0; i < attempts.length; i++) {
// Extract name and password from the attempt(s)
let name = attempts[i][0];
let password = attempts[i][1];
// If the name matches the object key and the password does not match the value...
if (name === key && password !== value) {
// Add this attempt to the mismatched passwords array
mismatchedPasswords.push(attempts[i]);
}
}
}
return mismatchedPasswords;
}
// Test the function!
console.log(findMismatchedPasswords([
["John", "J"],
["Mike", "Y"],
["Ion", "F"]
], {
"John": "J",
"Mike": "C",
"Ion": "I"
}));This code accomplishes your request, but there are more efficient ways to handle this scenario. For instance, entries that do not exist at all (e.g.
["Dave": "davina"]I have provided a basic solution here; feel free to enhance it further!
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