Unlocking the Power of Calculations with VueJS

I am looking to transform a string representing an IP address, like 10.120.0.1, into another string representing an ISIS Network ID, such as 49.0001.0101.2000.0001.00. The section in the middle 010 1.20 00.0 001 corresponds to the first string (I have added spaces for clarity). Each hextet in the ISIS Network ID consists of 4 digits that need to match with the corresponding 3 digits in the IP Address octet. For example, if the number is 53, it should be converted to 053 to maintain the format.

All IP addresses begin with 10.120., so I just need to replace the last 2 octets from the IP Address into the ISIS Network ID.

The goal is to create a dynamic system where inputting a new IP address in a field named loopbackIP automatically updates the value in the isisNetworkID field.

This is what I currently have:

49.0001.0101.{{ isisNetworkID }}.00

To achieve this, the remaining values from the input field linked by v-model="loopbackIP" need to fit within the middle part of the isisNetworkID following this pattern - xxxx.xxxx.

I've started with a computed calculation but unsure how to handle the conversion from 4 digits to 3...

const loopbackIP = '10.120.0.1';

const isisNetworkID = computed(() => {
    let idaho = '10.120.';

    if (loopbackIP.indexOf(idaho)) {
        return loopbackIP.slice(7);
    } else {
        console.log('Nothing is happening');
    }
});

I hope this explanation clarifies the issue...

Answer №1

Understanding your objective, let's break it down into manageable segments. Beginning with the IP address:

10.120.0.1

Your goal is to pad each part to 3 digits like so:

['010', '120', '000', '001']

This can be achieved by splitting the string at the . and utilizing String.prototype.padStart(). Afterwards, we concatenate the array elements:

'010120000001'
 ||||
 ^^^^ -> to be removed

The initial 4 digits are redundant, as per your template, hence we eliminate them using String.prototype.substring(4). Resulting in:

'20000001'

Now, divide this into groups of 4 characters each as shown here:

['2000', '0001']

...and combine them back with a period:

'2000.0001'

Finally, merge it back into a string. Below is a sample snippet demonstrating the desired outcome:

const loopbackIP = '10.120.0.1';
const parts = loopbackIP.split('.').map(x => x.padStart(3, '0'));

// Exclude the first 4 characters
let isisNetworkId = parts.join('');
isisNetworkId = isisNetworkId.substring(4);

const output = `49.0001.0101.${isisNetworkId.match(/.{4}/g).join('.')}.00`;
console.log(output);

To implement this logic in your VueJS code, simply follow this structure:

const loopbackIP = '10.120.0.1';

const isisNetworkID = computed(() => {
    const loopbackIP = '10.120.0.1';
    const parts = loopbackIP.split('.').map(x => x.padStart(3, '0'));

    let isisNetworkId = parts.join('');
    isisNetworkId = isisNetworkId.substring(4);

    // Concatenate, divide into 4-character chunks, recombine with periods
    return isisNetworkId.match(/.{4}/g).join('.');
});

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