Unambiguous clarification of the behavior of .sort() in this scenario

alert("0123456789".split("").sort(function(){return .5-Math.random()}).join(""));

If you're looking for a quick way to generate a random 10-digit number in JavaScript with the digits from 0 to 9 in a mixed-up order, this method is one of the shortest options available. For example, it could produce a number like 7205169483.

split("")//This function splits the string into individual characters
.sort(function(){return .5-Math.random()})
.join("")//Joins the characters back together with an empty separator

Have you ever wondered why {return Math.random()} wouldn't work in this context?

Do you know how many times the .sort() function is executed - just once or ten times sequentially?

Answer №1

Comments from @elclanrs emphasize that the sort function requires a callback function to compare two elements, a and b. The comparison should result in a negative number if a < b, 0 if a == b, and a positive number otherwise.

The frequency of sort function calls depends on the sorting algorithm's implementation. More details can be found in this thread.

In a given scenario, 0.5 - Math.Random() will yield either a negative or positive output because Math.Random() generates values between 0 and 1.

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