Unable to proceed with iteration

Question

Unable to proceed with iteration

I am encountering an issue with the ng-repeat directive while working on it. As a beginner, I am struggling to resolve it on my own.

var myModule = angular.module("myFirst",[]);

myModule.controller("cont", function($scope){
var employees = [
{name: "Manju", age :"23", rank:"2"},
{name: "SivaSankari", age :"23", rank:"1"},
{name: "Gayathri", age :"23", rank:"1"},
];
$scope.employees = employees;
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<html  ng-app="myFirst">
  <head>
    <title> My workout|ngRepeat
    </head>
<body>
<div ng-controller="cont">
<table>
<thead>
<th>Name</th>
<th>Age</th>
<th>Postions</th>
</thead>
<tbody>
<tr ng-repeat="x in employees">
<td>{{employees.name}}</td>
<td>{{employees.age}}</td>
<td>{{employees.position}}</td>
</tr>
</tbody>
</table>

</div>

</body>
  <html>

Additionally, I am unsure about the key 'x'. Is it acceptable to assign any key value? Can someone please assist me in resolving and understanding this? Thank you.

javascript angularjs

Answer 1

Answer №1

First Tip

In order to access the current item in the array, use x instead of employees. Remember, employees is the array itself and x represents the current item in the loop.

Second Tip

It seems like you were trying to access a property called position, which does not exist in your object. Instead, make sure to refer to the correct property name, which is rank.

var myModule = angular.module("myFirst", []);

myModule.controller("cont", function($scope) {
  var employees = [{
    name: "Manju",
    age: "23",
    rank: "2"
  }, {
    name: "SivaSankari",
    age: "23",
    rank: "1"
  }, {
    name: "Gayathri",
    age: "23",
    rank: "1"
  }, ];
  $scope.employees = employees;
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<html ng-app="myFirst">

<body>
  <div ng-controller="cont">
    <table>
      <thead>
        <th>Name</th>
        <th>Age</th>
        <th>Positions</th>
      </thead>
      <tbody>
        <tr ng-repeat="x in employees">
          <td>{{x.name}}</td>
          <td>{{x.age}}</td>
          <td>{{x.rank}}</td>
        </tr>
      </tbody>
    </table>

  </div>

</body>
<html>

Answer 2

First Tip

In order to access the current item in the array, use x instead of employees. Remember, employees is the array itself and x represents the current item in the loop.

Second Tip

It seems like you were trying to access a property called position, which does not exist in your object. Instead, make sure to refer to the correct property name, which is rank.

var myModule = angular.module("myFirst", []);

myModule.controller("cont", function($scope) {
  var employees = [{
    name: "Manju",
    age: "23",
    rank: "2"
  }, {
    name: "SivaSankari",
    age: "23",
    rank: "1"
  }, {
    name: "Gayathri",
    age: "23",
    rank: "1"
  }, ];
  $scope.employees = employees;
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<html ng-app="myFirst">

<body>
  <div ng-controller="cont">
    <table>
      <thead>
        <th>Name</th>
        <th>Age</th>
        <th>Positions</th>
      </thead>
      <tbody>
        <tr ng-repeat="x in employees">
          <td>{{x.name}}</td>
          <td>{{x.age}}</td>
          <td>{{x.rank}}</td>
        </tr>
      </tbody>
    </table>

  </div>

</body>
<html>

Answer 3

Answer №2

This is the recommended format:

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 4

This is the recommended format:

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 5

Answer №3

It is recommended to access the attributes of x rather than the employee array

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 6

It is recommended to access the attributes of x rather than the employee array

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 7

Answer №4

When you iterate over the employees, you define x as the employee. The repeat section should look like this:

<tr ng-repeat="x in employees">
<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>
</tr>

Answer 8

When you iterate over the employees, you define x as the employee. The repeat section should look like this:

<tr ng-repeat="x in employees">
<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>
</tr>

Answer 9

Answer №5

When utilizing the syntax ng-repeat="x in employees", you are essentially instructing the program to assign each item to the variable x during each iteration. This is why you are limited to using only the variable x within the loop.

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 10

When utilizing the syntax ng-repeat="x in employees", you are essentially instructing the program to assign each item to the variable x during each iteration. This is why you are limited to using only the variable x within the loop.

<td>{{x.name}}</td>
<td>{{x.age}}</td>
<td>{{x.position}}</td>

Answer 11

Answer №6

Your ngRepeat usage in the title tag is unclear, and the way you are declaring your table is confusing.

<tr ng-repeat="x in employees">

This code signifies that for each element (referred to as x) in the array employees, it will repeat that element as a table row. Please ensure this is the desired behavior.

Therefore, within your td element, you should include:

<td>{{x.name}}</td>

I am also unsure about using x as the key. Is it acceptable to use any key value?

If you are asking if you can use a different name instead of x, then yes, you can change it. For example:

<tr ng-repeat="singleEmployee in employees">
<td>{{singleEmployee.name}}</td>

Answer 12

Your ngRepeat usage in the title tag is unclear, and the way you are declaring your table is confusing.

<tr ng-repeat="x in employees">

This code signifies that for each element (referred to as x) in the array employees, it will repeat that element as a table row. Please ensure this is the desired behavior.

Therefore, within your td element, you should include:

<td>{{x.name}}</td>

I am also unsure about using x as the key. Is it acceptable to use any key value?

If you are asking if you can use a different name instead of x, then yes, you can change it. For example:

<tr ng-repeat="singleEmployee in employees">
<td>{{singleEmployee.name}}</td>

Answer 13

Answer №7

The problem lies in the ng-repeat statement. Instead of using employess.name, it should be x.name.

 <tr ng-repeat="x in employees">
    <td>{{x.name}}</td>
    <td>{{x.age}}</td>
    <td>{{x.position}}</td>
    </tr>

Answer 14

The problem lies in the ng-repeat statement. Instead of using employess.name, it should be x.name.

 <tr ng-repeat="x in employees">
    <td>{{x.name}}</td>
    <td>{{x.age}}</td>
    <td>{{x.position}}</td>
    </tr>

Unable to proceed with iteration

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

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