Unable to open new window on iOS devices using $window.open

 alertPopup.then (function(res) {
      if(ionic.Platform.isAndroid()) {
        $window.open('android_link_here', '_system')
      }

      else if(ionic.Platform.isIOS()) {
        $window.open('ios_link_here', '_system')
      }

      else {
        $window.open('other_link_here', '_system');
      }

    })

Hey everyone, I am in the process of setting up a popup notification for users to inform them about a new version of the application being available. The goal is for this popup to direct users to a specific webpage using the links provided. However, I've encountered an issue with iOS where it fails to open Safari and load the intended page. At this moment, I haven't tested this functionality on Android.

I may be making an error in my approach, but after searching around, I couldn't find anyone else experiencing the same problem.

Answer №1

Once the alertPopup function is completed, the reference to the $window element will no longer be available.

To address this issue, a potential solution would be to maintain a local reference to the $window object and utilize that instead of directly accessing $window.

let windowRef = $window;

alertPopup.then(function(res) {
      if(ionic.Platform.isAndroid()) {
        windowRef.open('android_link_here', '_system')
      }

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