Traverse the array of nested JSON objects in an iterative manner

Question

Traverse the array of nested JSON objects in an iterative manner

I need to iterate through a JSON array object with the following structure:

var myJSONObject = {
    "abc": {
        "prod_1": [
            {"prod_ver" : "prod 1 ver 1"},
            {"prod_ver" : "prod 1 ver 2"},
        ],
        "prod_2": [
            {"prod_ver" : "prod 2 ver 1"},
            {"prod_ver" : "prod 2 ver 2"},
        ],
        "prod_3": [
            {"prod_ver" : "prod 3 ver 1"},
            {"prod_ver" : "prod 3 ver 2"},
        ]
    }
};

The task involves looping through the product names and their respective versions. Each product name contains a list of its versions.

I am looking for a JavaScript solution that can handle multiple products and versions dynamically, providing the product name and version separately in variables for further processing.

If there is a better JSON structure or any suggestions for improvement, please advise on the appropriate format.

Your assistance is much appreciated.

javascript json

Answer 1

Answer №1

In order to improve the structure of your JSON data, it would be beneficial to define the property abc as an array since it contains a list of products. You can do this by redefining it like so:

var myJSONObject = 
{
"abc":
    [
        [
            {"prod_ver" : "prod 1 ver 1"},
            {"prod_ver" : "prod 1 ver 2"},
        ],
        [
            {"prod_ver" : "prod 2 ver 1"},
            {"prod_ver" : "prod 2 ver 2"},
        ],
        [
            {"prod_ver" : "prod 3 ver 1"},
            {"prod_ver" : "prod 3 ver 2"},
        ]
    ]
};

By structuring your data in this way, you can easily iterate over the products and their versions using standard loops:

for(var i = 0; i < myJSONObject.abc.length; i++)
{
    var product = myJSONObject.abc[i];
    for(var j = 0; j < product.length; j++)
    {
        var version = product[j];
    }
}

If you want to enhance the readability of your JSON object further, you could consider adjusting its structure slightly:

var catalog = 
{
    "products": [
        {
            "name": "prod 1",
            "versions": [
                "ver 1",
                "ver 2"
            ]
        },
        {
            "name": "prod 2",
            "versions": [
                "ver 1",
                "ver 2"
            ]
        }
    ]
};

for(var i = 0; i < catalog.products.length; i++)
{
    var product = catalog.products[i];
    var productName = product.name;
    for(var j = 0; j < product.versions.length; j++)
    {
        var version = product.versions[j];
    }
}

Answer 2

In order to improve the structure of your JSON data, it would be beneficial to define the property abc as an array since it contains a list of products. You can do this by redefining it like so:

var myJSONObject = 
{
"abc":
    [
        [
            {"prod_ver" : "prod 1 ver 1"},
            {"prod_ver" : "prod 1 ver 2"},
        ],
        [
            {"prod_ver" : "prod 2 ver 1"},
            {"prod_ver" : "prod 2 ver 2"},
        ],
        [
            {"prod_ver" : "prod 3 ver 1"},
            {"prod_ver" : "prod 3 ver 2"},
        ]
    ]
};

By structuring your data in this way, you can easily iterate over the products and their versions using standard loops:

for(var i = 0; i < myJSONObject.abc.length; i++)
{
    var product = myJSONObject.abc[i];
    for(var j = 0; j < product.length; j++)
    {
        var version = product[j];
    }
}

If you want to enhance the readability of your JSON object further, you could consider adjusting its structure slightly:

var catalog = 
{
    "products": [
        {
            "name": "prod 1",
            "versions": [
                "ver 1",
                "ver 2"
            ]
        },
        {
            "name": "prod 2",
            "versions": [
                "ver 1",
                "ver 2"
            ]
        }
    ]
};

for(var i = 0; i < catalog.products.length; i++)
{
    var product = catalog.products[i];
    var productName = product.name;
    for(var j = 0; j < product.versions.length; j++)
    {
        var version = product.versions[j];
    }
}

Answer 3

Answer №2

myJSONObject.abc is an object containing keys such as prod_1, prod_2, and so on. By using a for-in loop, you can iterate through the keys of an object like this:

var productName;
var productVersionArray;

for (productName in myJSONObject.abc) {
    productVersionArray = myJSONObject.abc[productName];
}

It's important to note that the order of the keys may vary depending on the JavaScript engine being used. To control the order, you can obtain an array of keys, sort them, and then loop through the sorted array. In environments supporting ES5, you can get an array of keys using Object.keys(yourObject). For older browsers, a shim would be required.

Within the loop, you can further iterate through the array using a standard for loop:

for (versionIndex = 0; versionIndex < productVersionArray.length; ++versionIndex) {
    // Access `productVersionArray[versionIndex].prod_ver` here
}

The following example demonstrates putting these concepts into practice:

(function() {

  var myJSONObject = 
    {
    "abc":
        {
            "prod_1": 
            [
                {"prod_ver" : "prod 1 ver 1"},
                {"prod_ver" : "prod 1 ver 2"}
            ],

            "prod_2": 
            [
                {"prod_ver" : "prod 2 ver 1"},
                {"prod_ver" : "prod 2 ver 2"}
            ],
            "prod_3": 
            [
                {"prod_ver" : "prod 3 ver 1"},
                {"prod_ver" : "prod 3 ver 2"}
            ]
        }
    };

  var productName;
  var productVersionArray;
  var versionIndex;

  for (productName in myJSONObject.abc) {
      productVersionArray = myJSONObject.abc[productName];
      display(productName + " has " + productVersionArray.length + " versions listed");
      for (versionIndex = 0; versionIndex < productVersionArray.length; ++versionIndex) {
        display("* " + productVersionArray[versionIndex].prod_ver);
      }
  }

  function display(msg) {
    var p = document.createElement('p');
    p.innerHTML = String(msg);
    document.body.appendChild(p);
  }

})();

Live Example | Source Code

Answer 4

myJSONObject.abc is an object containing keys such as prod_1, prod_2, and so on. By using a for-in loop, you can iterate through the keys of an object like this:

var productName;
var productVersionArray;

for (productName in myJSONObject.abc) {
    productVersionArray = myJSONObject.abc[productName];
}

It's important to note that the order of the keys may vary depending on the JavaScript engine being used. To control the order, you can obtain an array of keys, sort them, and then loop through the sorted array. In environments supporting ES5, you can get an array of keys using Object.keys(yourObject). For older browsers, a shim would be required.

Within the loop, you can further iterate through the array using a standard for loop:

for (versionIndex = 0; versionIndex < productVersionArray.length; ++versionIndex) {
    // Access `productVersionArray[versionIndex].prod_ver` here
}

The following example demonstrates putting these concepts into practice:

(function() {

  var myJSONObject = 
    {
    "abc":
        {
            "prod_1": 
            [
                {"prod_ver" : "prod 1 ver 1"},
                {"prod_ver" : "prod 1 ver 2"}
            ],

            "prod_2": 
            [
                {"prod_ver" : "prod 2 ver 1"},
                {"prod_ver" : "prod 2 ver 2"}
            ],
            "prod_3": 
            [
                {"prod_ver" : "prod 3 ver 1"},
                {"prod_ver" : "prod 3 ver 2"}
            ]
        }
    };

  var productName;
  var productVersionArray;
  var versionIndex;

  for (productName in myJSONObject.abc) {
      productVersionArray = myJSONObject.abc[productName];
      display(productName + " has " + productVersionArray.length + " versions listed");
      for (versionIndex = 0; versionIndex < productVersionArray.length; ++versionIndex) {
        display("* " + productVersionArray[versionIndex].prod_ver);
      }
  }

  function display(msg) {
    var p = document.createElement('p');
    p.innerHTML = String(msg);
    document.body.appendChild(p);
  }

})();

Live Example | Source Code

Answer 5

Answer №3

Enhanced using ES6 syntax

  let { items } =
    {
        "items": [
            {
                "title": "item 1",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            },
            {
                "title": "item 2",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            },
            {
                "title": "item 3",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            }
        ]
    };

    const stockList = items.reduce((previous, current) => {
        let { title, options } = current;
        previous[title] = options
        return previous
    }, []);

    Object.entries(stockList).forEach((item) => {
        let itemName = item[0];
        let itemOptions = item[1].join(", ");
    });

Answer 6

Enhanced using ES6 syntax

  let { items } =
    {
        "items": [
            {
                "title": "item 1",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            },
            {
                "title": "item 2",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            },
            {
                "title": "item 3",
                "options": [
                    "opt 1",
                    "opt 2"
                ]
            }
        ]
    };

    const stockList = items.reduce((previous, current) => {
        let { title, options } = current;
        previous[title] = options
        return previous
    }, []);

    Object.entries(stockList).forEach((item) => {
        let itemName = item[0];
        let itemOptions = item[1].join(", ");
    });

Answer 7

Answer №4

function outputProperties() {
  for (let property in myJSONObject.xyz) {
    let propValue = myJSONObject.xyz[property];
    for (let j = 0; j <= propValue.length; j++) {
      console.log(propValue[[j]]);
    }
  }
}

Answer 8

function outputProperties() {
  for (let property in myJSONObject.xyz) {
    let propValue = myJSONObject.xyz[property];
    for (let j = 0; j <= propValue.length; j++) {
      console.log(propValue[[j]]);
    }
  }
}

Traverse the array of nested JSON objects in an iterative manner

Answer №1

Answer №2

Answer №3

Answer №4

Similar questions

Error message in my Angular project: Invalid Target Error

How can I eliminate the hover effect from a div element?

How can we combine multiple arrays into a single JSON object using json_encode in PHP?

Angular 9: Chart.js: Monochromatic doughnut chart with various shades of a single color

Breaking down nested date lists within DataFrame columns to calculate the average hour

Issue encountered while parsing JSON data in FastAPI: JSON.parse error - unexpected end of data at line 1 column 1

When Ajax sends an HTTP Get request to an MVC Controller with a complex JSON object as a parameter, the controller receives it as null

Activate onbeforeunload when the form is not submitted

Leveraging Watchers on props in Vue 3's Script Setup

What steps should be taken to retrieve the contents of a file that has been chosen using the browse

Fill a grid child with an excessive amount of content without specifying a fixed height

Switching to '@mui/material' results in the components failing to render

Basic AngularJS application, however I am receiving {{this is supposed to be the information}}

The Slider component in Material UI's API may not properly render when using decimal numbers as steps or marks in React

Setting up Npm Sequelize Package Installation

Having issues transferring the variable from JavaScript to PHP?

What is the best way to hide the jQuery modal I created?

Implement a button transformation upon successful completion of a MySQLi update using AJAX

Next JS is successfully importing external scripts, however, it is failing to run them as

Ways to expand a Bootstrap input field by clicking on it: