Consider the following object:
{
"apples": [
"one",
"two"
],
"oranges": [
"three",
"four"
]
}
If I want to find the value four within this object, how can I do so efficiently? Would a loop work, like the one shown below?
for (var i=0; i < obj.length; i++) {
for (var y=0; y <obj.childObj.length; y++ {
obj.childObj[i] === 'four' ? return : null;
}
}
Alternatively, is there a more optimal way to organize and search through this data structure?
for(var key in object)
if(object.hasOwnProperty(key)) {
for(var nestedKey in object[key])
if(object[key].hasOwnProperty(nestedKey)) {
object[key][nestedKey] === 'four' ? performAction() : performAnotherAction();
}
}
MODIFY: Enhancement per recommendation from Matthew Herbst
To iterate through the elements in an object, you can utilize the for (x in y) statement:
var items = {
"apples": [
"red",
"green"
],
"oranges": [
"orange",
"tangerine"
]
};
for (var category in items) {
var itemList = items[category];
for (var i=0; i <itemList.length; i++) {
// itemList[i] === 'green' ? return : null;
console.log(itemList[i]);
}
}
The output of this code snippet will be:
red
green
orange
tangerine
If you're on a quest to uncover whether this particular item contains the number four
var isFourPresent = Object.keys(obj).filter(function(val){ return obj[val].indexOf("four") != -1 }).length > 0;
To broaden its applicability
function findY(y)
{
return Object.keys(obj).filter(function(val){ return obj[val].indexOf(y) != -1 }).length > 0;
}
Give this a shot ;)
Tweaked your script:
for (let x = 0; x < newArr.length; x++) {
for (let y = 0; y < newArr[x].length; y++ {
if(newArr[x][y] === 'four'){
console.log("It's four");
}
}
}
To find a specific element in an object, you can utilize the indexOf method.
var fruits={
"apples": [
"one",
"two"
],
"oranges": [
"three",
"four"
]
}
for (var key in fruits) {
if (fruits[key].indexOf("four") > -1)
console.log("The element 'four' was found");
}
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