Transforming an array into key-value pairs where the keys are odd elements and the values are even elements

Question

Transforming an array into key-value pairs where the keys are odd elements and the values are even elements

Is there a straightforward way to transform this initial array:

[
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
]

Into the desired array below:

[
    {"Bargain": "deal"},
    {"Consistent": "Steady; regular"},
    {"Accurately": "a thing bought or offered for sale much more cheaply than is usual or expected."},
    {"Charge": "demand (an amount) as a price for a service rendered or goods supplied."}
]

I have attempted filtering elements from two separate arrays, but it seems overly complicated. Is there an easier solution to achieve this?

(Acknowledging that the definition for 'Accurately' may be unconventional)

javascript arrays

Answer 1

Answer №1

Here is a way to achieve the desired outcome using a basic for loop:

const items = [
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
];

let resultArray = [];

for (let i = 0; i < items.length; i += 2) {
  resultArray.push({
    [items[i]]: items[i + 1]
  });
}

console.log(resultArray);

Answer 2

Here is a way to achieve the desired outcome using a basic for loop:

const items = [
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
];

let resultArray = [];

for (let i = 0; i < items.length; i += 2) {
  resultArray.push({
    [items[i]]: items[i + 1]
  });
}

console.log(resultArray);

Answer 3

Answer №2

To implement this functionality, you can utilize the Array.from method in the following manner:

const elements = [
  "Sun",
  "Moon",
  "Stars",
  "Planets",
  "Galaxy",
  "Universe",
  "Sky",
  "Earth"
]

const size = Math.ceil(elements.length / 2)

const result = Array.from({ size }, (_, index) =>
   ({ [elements[index*2]]: elements[index*2+1] })
);

console.log(result)

Answer 4

To implement this functionality, you can utilize the Array.from method in the following manner:

const elements = [
  "Sun",
  "Moon",
  "Stars",
  "Planets",
  "Galaxy",
  "Universe",
  "Sky",
  "Earth"
]

const size = Math.ceil(elements.length / 2)

const result = Array.from({ size }, (_, index) =>
   ({ [elements[index*2]]: elements[index*2+1] })
);

console.log(result)

Transforming an array into key-value pairs where the keys are odd elements and the values are even elements

Answer №1

Answer №2

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