Transforming a series of digits into a numerical value

Question

Transforming a series of digits into a numerical value

After analyzing the given array of strings:

["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"]

I came up with this reduce function to convert the array into a single number without using any predefined parsers.

d.reduce((res,n,idx)=>{
   res *= 10;
   res += n.charCodeAt(0) - 48;
   console.log(res);
   return res;
},0);

The output log is as follows:

9
93
933
9333
93338
933385
9333852
93338527
933385270
9333852702
93338527022
933385270222
9333852702227
93338527022279
933385270222798
9333852702227988

933385270222798(8) <-- The expected value is 7

Further observation shows that

9333852702227980 + 7 = 9333852702227988

, indicating an issue when handling large numbers. This signals a possible overflow error due to exceeding safe Integer limits. Any suggestions on how to rectify this?

javascript arrays reduce parseint

Answer 1

Answer №1

function arrayToNumber(arr) {
    let final = ""
    for (element of arr) {
        final += element
    }
    return final
}

let numbersArray = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"]
console.log(Number(arrayToNumber(numbersArray)))

Answer 2

function arrayToNumber(arr) {
    let final = ""
    for (element of arr) {
        final += element
    }
    return final
}

let numbersArray = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"]
console.log(Number(arrayToNumber(numbersArray)))

Answer 3

Answer №2

To begin, you will need to convert the data into a string, and then utilize the replaceAll function to replace all the commas within the created string:

const arr = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"]
const no = (arr.toString()).replaceAll(',','');
console.log("After replacing commas: ", no)

Answer 4

To begin, you will need to convert the data into a string, and then utilize the replaceAll function to replace all the commas within the created string:

const arr = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"]
const no = (arr.toString()).replaceAll(',','');
console.log("After replacing commas: ", no)

Answer 5

Answer №3

Consider exploring libraries for high-precision integer calculations, such as Big Numbers, Big, or Crunch. These resources can offer insights on developing your own solution.

Answer 6

Consider exploring libraries for high-precision integer calculations, such as Big Numbers, Big, or Crunch. These resources can offer insights on developing your own solution.

Answer 7

Answer №4

const array = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"];
let sum = 0;

for (let i = array.length - 1; i >= 0; i--) {
  sum += array[i] * Math.pow(10, (array.length - 1) - i);
}

Number.prototype.addTogether = function(x) {
  let result = 0;
  for (let j = array.length - 1; j >= 0; j--) {
    result += (array[j] * 1 + (x[(array.length - 1) - j] || 0) * 1) * Math.pow(10, (array.length - 1) - j);
  }
  return result;
}

console.log(sum);
console.log(sum.addTogether('7'));

Answer 8

const array = ["9", "3", "3", "3", "8", "5", "2", "7", "0", "2", "2", "2", "7", "9", "8", "7"];
let sum = 0;

for (let i = array.length - 1; i >= 0; i--) {
  sum += array[i] * Math.pow(10, (array.length - 1) - i);
}

Number.prototype.addTogether = function(x) {
  let result = 0;
  for (let j = array.length - 1; j >= 0; j--) {
    result += (array[j] * 1 + (x[(array.length - 1) - j] || 0) * 1) * Math.pow(10, (array.length - 1) - j);
  }
  return result;
}

console.log(sum);
console.log(sum.addTogether('7'));

Transforming a series of digits into a numerical value

Answer №1

Answer №2

Answer №3

Answer №4

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