Transform the image data retrieved from an external API into the appropriate format for displaying on the webpage

When I make a call to an external API, it returns image data that I want to render on my page.

However, the response looks like this when I log it to the console:

https://i.stack.imgur.com/GpDhH.png

I'm not very familiar with image formats, so I've been searching online to find out how to convert this type of return to the necessary format for displaying it on my page, but I haven't had any luck.

This is how my API call is set up:

 $.ajax({
        type: 'GET',
        beforeSend: function (xhr) {
            xhr.setRequestHeader('t', ts);
        },
        url: "https://someservice.com/DataService.svc/ConsumerMedia(guid'" + imageQuid + "')/$value",
        data: rBody,
        cache: true,
        contentType: "image/png",
        dataType: "text",
        success: function (data) {
            console.log(data);

            // Convert data to relevant format here
            // Then display image as below

            $('#photo').attr("src", "data:image/png;base64," + data + "");
        },
        error: function (request, error) {

        }
    });

If anyone can offer guidance on how to format the response in order to display it on the page, I would greatly appreciate it.

Answer №1

Update: After attempting to utilize jQuery ajax without success (due to limitations with binary/arraybuffer response type or my inability to locate the proper methods), I was able to achieve the desired outcome using XHR instead:

var xhr = new XMLHttpRequest();
xhr.open("GET", "https://someservice.com/DataService.svc/ConsumerMedia(guid'" + imageQuid + "')/$value", true);
xhr.responseType = 'arraybuffer';

xhr.onload = function(e) {
    if (this.status == 200) {
        var blob = new Blob([this.response], {type: "image/png"});
        var reader = new FileReader();
        reader.readAsDataURL(blob);
        reader.onloadend = function() {
            $('#photo').attr("src", reader.result);
        }
    }
};

xhr.send();

It may be necessary to make some adjustments in order to mirror the functionality of the original ajax request.

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