Transform the array by utilizing its own elements

Question

Transform the array by utilizing its own elements

I came up with a solution to a problem I was facing, but I'm not entirely comfortable with it. It feels risky to me, like using an array to redefine itself is not a good coding practice. It's similar to trying to explain a word by using the word itself in the definition. Can someone please help me understand why this approach might be incorrect, or if it's actually acceptable?

let array = []

// other actions are performed to populate the array

array = array.filter(element => element !== true)

I chose to go this route because I need to keep the variable name (array) consistent throughout the function. The array's contents could be modified multiple times before it's finally returned, depending on other actions taking place within the function.

If this explanation is unclear, please let me know so I can provide more details. Thank you!

javascript arrays

Answer 1

Answer №1

There's no need to worry. The portion on the right side (

array.filter(element => element !== true)

) of the equation is executed initially, creating a brand new array before being reassigned to the original array.

Answer 2

There's no need to worry. The portion on the right side (

array.filter(element => element !== true)

) of the equation is executed initially, creating a brand new array before being reassigned to the original array.

Answer 3

Answer №2

If you want to efficiently remove items from an array without creating a new array and reassigning values, you can loop through the array backwards.

for (let i = array.length - 1; i >= 0; --i) {
  if (!!array[i]) {
    array.splice(i, 1);
  }
}

This approach offers multiple benefits:

It is a fast solution.
It is memory efficient.
It does not interfere with any other code that relies on the original array reference.

Answer 4

If you want to efficiently remove items from an array without creating a new array and reassigning values, you can loop through the array backwards.

for (let i = array.length - 1; i >= 0; --i) {
  if (!!array[i]) {
    array.splice(i, 1);
  }
}

This approach offers multiple benefits:

It is a fast solution.
It is memory efficient.
It does not interfere with any other code that relies on the original array reference.

Transform the array by utilizing its own elements

Answer №1

Answer №2

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