Transform the appearance of several elements using querySelectorAll

When targeting class names in an HTML page with a checkbox using querySelectorAll, keep in mind that getElementByID only works with the first element. QuerySelectorAll displays a nodeList which might require some corrections - how can this be achieved?

let salesCheckbox = document.getElementById('sales-checkbox');
let euroSalesCurrency = document.querySelectorAll('.euro-sales-currency');
let originalSalesCurrency = document.querySelectorAll('.original-sales-currency');

if (salesCheckbox) {
    salesCheckbox.addEventListener('click', saleCheckbox);
}

//Function to close thirty
function saleCheckbox() {
    euroSalesCurrency.style.display = 'none';
    originalSalesCurrency.style.display = "block";

}

I am looking to show a span element when the user checks the checkbox and hide it when unchecked.

Answer №1

In order to hide each node within the querySelectorAll, you must loop through them.

Here is a sample code snippet:

document.querySelectorAll('.euro-sales-currency').forEach(item => item.style.display = 'none')

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