Transform an Array by replacing a specific value or creating a new one

Question

Transform an Array by replacing a specific value or creating a new one

Dealing with two arrays, both potentially of large lengths:

The goal is to update the status in Array 1 with the corresponding status from Array 2. Here's a sample output:

[{
value: 123,
status: 'demo',
type: '...'
},
{value: 2335,
 status: 'demo2',
 type: 'xxx'
}]

The key challenge here lies in efficiently replacing the status values between the two arrays given their potential size. The order and length may vary, hence requiring strategic linking based on IDs.

Original Data

[
   {
    "id": "55",
    "status": "2",
    "type": "COD",
     "value": "5038.2",
   },
 {
   "id": "56",
   "status": "2",
   "type": "COD",
    "value": "5398.2",
  },
   {
    "id": "57",
    "status": "2",
    "type": "COD",
    "value": "10798.2",
  }

 ]

Array 2

[
   {
     "id": "1",
    "status": "Awaiting Confirmation",
   },
   {
    "id": "2",
    "status": "Confirmed",
   },
   {
    "id": "3",
     "status": "Awaiting Shipment",
  },
  {
     "id": "4",
    "status": "Awaiting Pickup",
   },
   {
    "id": "5",
    "status": "Shipped",
   },
 {
   "id": "6",
    "status": "Delivered",
   },
   {
     "id": "7",
    "status": "Cancelled",
  },
  {
   "id": "8",
    "status": "Refund Requested",
   },
   {
     "id": "9",
     "status": "Refunded",
   }

Attempted Solutions: Utilized lodash library along with a for loop

const output = [];
      for (let i = 0; i < array1.length; i++) {
        const statuscode = array1[i].status;
        const result = _.find(array2, { id: statuscode });
        output.push({
          value: array1[i].value,
          status: result.status,
          type: array1[i].type
        });
      }
      console.log(output);

javascript arrays

Answer 1

Answer №1

To optimize performance, consider converting one of the arrays into a Map first. Map lookups are highly efficient:

const data = [{
    id: 1,
    name: 'Alice',
  },
  {
    id: 2,
    name: 'Bob',
  }
];
const map = new Map(Object.values(data).map(({ id, name }) => [id, name]));
console.log(map.get(1)); // Output: Alice

In terms of code readability, it's important to prioritize that over speed. However, if you prefer performance and want to use a for loop instead of .map, here's an example:

const items = [{
    num: 1,
    value: 'first'
  },
  {
    num: 2,
    value: 'second'
  }
];
const itemMap = new Map(items.map(({ num, value }) => [num, value]));

const result = [];
for (let i = 0; i < items.length; i++) {
  const { num, value } = items[i];
  result.push({ num: num, value: itemMap.get(num) });
}
console.log(result);

Answer 2

To optimize performance, consider converting one of the arrays into a Map first. Map lookups are highly efficient:

const data = [{
    id: 1,
    name: 'Alice',
  },
  {
    id: 2,
    name: 'Bob',
  }
];
const map = new Map(Object.values(data).map(({ id, name }) => [id, name]));
console.log(map.get(1)); // Output: Alice

In terms of code readability, it's important to prioritize that over speed. However, if you prefer performance and want to use a for loop instead of .map, here's an example:

const items = [{
    num: 1,
    value: 'first'
  },
  {
    num: 2,
    value: 'second'
  }
];
const itemMap = new Map(items.map(({ num, value }) => [num, value]));

const result = [];
for (let i = 0; i < items.length; i++) {
  const { num, value } = items[i];
  result.push({ num: num, value: itemMap.get(num) });
}
console.log(result);

Answer 3

Answer №2

An easy way to accomplish this task is with a standard `for` loop:

for (let i = 0; i < array1.length; i++) {
  array1[i].status = array2[i].status;
}

This method assumes that both arrays are the same length and in the same order.

UPDATE

If you need to handle different lengths or orders, consider using Array.prototype.find:

for (let i = 0; i < array1.length; i++) {
  const temp = array1[i];
  temp.status = array2.find(x => x.id === temp.status).status;
}

Remember, it's important to prioritize readability over premature optimization for better code maintenance.

Answer 4

An easy way to accomplish this task is with a standard `for` loop:

for (let i = 0; i < array1.length; i++) {
  array1[i].status = array2[i].status;
}

This method assumes that both arrays are the same length and in the same order.

UPDATE

If you need to handle different lengths or orders, consider using Array.prototype.find:

for (let i = 0; i < array1.length; i++) {
  const temp = array1[i];
  temp.status = array2.find(x => x.id === temp.status).status;
}

Remember, it's important to prioritize readability over premature optimization for better code maintenance.

Transform an Array by replacing a specific value or creating a new one

Answer №1

Answer №2

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