To display a pattern with a series of alternating addition and subtraction operators, starting from -1 and ending at n, use JavaScript to iterate through the numbers and implement the pattern -1+

I've been struggling to locate the values despite numerous attempts. What steps can I take to resolve this issue? Below is my code snippet:

var numVal = prompt("");
for (var i = 1; i <= numVal; i++) {

  if (i % 2 !== 0) {
    console.log("-");
    document.write("-");
    // console.log(i);
    document.write(i);
  } else {
    console.log("+");
    document.write("+");
    // console.log(i);
    document.write(i);
  }

}
document.write("=", );

Answer №1

Give this a try:

let userInput = prompt("Enter a number:");
let result = 0;
for (let i = 1; i <= userInput; i++) {

  if (i % 2 !== 0) {
    document.write("-");
    document.write(i);
    result -= i;
  } else {
    document.write("+");
    document.write(i);
    result += i;
  }

}
document.write("=" + result);

Answer №2

An elegant solution for the problem at hand, especially appealing to advocates of declarative programming.

const func = (n) => {
[...Array(n)].map( (_,i) => (
    i%2 === 0 ? console.log(`-${i+1}`) : console.log(`+${i+1}`)
))}

func(6)

This code snippet is sure to get the job done effectively.

Answer №3

Check out the solution below, along with a link to the fiddle.

function createPattern(num) {
    let pattern = '';

  for (let i = 1; i <= num; i++) {
    if (i % 2 === 1) {
        pattern += `*${i}`; // Odd
    } else {
      pattern += `#${i}`; // Even
    }
  }

  return pattern += ` : ${num}`;
}

console.log(createPattern(7));

Answer №4

Here is a simple code snippet that may assist you.

let flag = true;
let result = 0;
let str = "";
let n = 10;

for(let i = 1; i < n; i++){
    if(flag){
        str += "-"; 
        result -= i;
    } else {
        str += "+";
        result += i;
    }
    str += i;
    flag = !flag;
}

str += "=" + result;
console.log(str);

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