Tips for utilizing filters to search through various key values within an array of objects

Question

Tips for utilizing filters to search through various key values within an array of objects

In my collection of wines, each wine is represented by an object with specific data:

var wines = [
  { _id: '59a740b8aa06e549918b1fda',
    wineryName: 'Some Winery',
    wineName: 'Pinot Noir',
    wineColor: 'Red',
    imageLink: '/img/FortBerensPN.png' },
  { _id: '59a7410aaa06e549918b1fdb',
    wineryName: 'Some Winery',
    wineName: 'Pinot Gris',
    wineColor: 'White',
    imageLink: '/img/FortBerensPG.png' },
  { _id: '59a74125aa06e549918b1fdc',
    wineryName: 'Some Winery',
    wineName: 'Rose',
    wineColor: 'Rose',
    imageLink: '/img/FortBerensRose.png' },
  { _id: '59a74159aa06e549918b1fdd',
    wineryName: 'Some other Winery',
    wineName: 'Rose',
    wineColor: 'Rose',
    imageLink: '/img/FortBerensRose.png' },
  { _id: '59a7417aaa06e549918b1fde',
    wineryName: 'Some other Winery',
    wineName: 'Pinot Gris',
    wineColor: 'White',
    imageLink: '/img/FortBerensPG.png' },
  { _id: '59a8721f4fd43b676a1f5f0d',
    wineryName: 'Some other Winery',
    wineName: 'Pinot Gris',
    wineColor: 'White',
    imageLink: '/img/FortBerensPG.png' },
  { _id: '59a872244fd43b676a1f5f0e',
    wineryName: 'Winery 3',
    wineName: 'Pinot Noir',
    wineColor: 'Red',
    imageLink: '/img/FortBerensPN.png' } ]

I'm trying to search for a wine object in a case-insensitive manner by specifying the key to search in with the following code:

var search = 'Noir'

filteredWines = function () {
  return wines.filter(function(wine){
    return (wine.wineName.toLowerCase().indexOf(search.toLowerCase())>=0;
  });
};

This code snippet returns:

[ { _id: '59a740b8aa06e549918b1fda',
    wineryName: 'Some Winery',
    wineName: 'Pinot Noir',
    wineColor: 'Red',
    imageLink: '/img/FortBerensPN.png' },
  { _id: '59a872244fd43b676a1f5f0e',
    wineryName: 'Winery 3',
    wineName: 'Pinot Noir',
    wineColor: 'Red',
    imageLink: '/img/FortBerensPN.png' } ]

However, searches for var search = 'Winery 3' or var search = 'red' do not yield any results because the search is limited to the wineName key in each object.

Is there a way to expand the search to include all key values, or even better, search multiple specified key values and return an array of matching objects?

Could a solution involve using filter or another method to achieve this, maybe something like:

filteredWines = function () {
  return wines.filter(function(wine){
    return ((wine.wineName.toLowerCase() && wine.wineName.toLowerCase() 
          && wine.wineName.toLowerCase()).indexOf(search.toLowerCase())>=0;
  });
};

Or am I on the wrong track completely?

Any suggestions or insights on a better way to accomplish this within Vue.js 2 would be greatly appreciated!

javascript arrays vue.js filtering vuejs2

Answer 1

Answer №1

A more versatile approach would be to create a function that scans through all the properties for a specific string. By iterating through all property values using Object.values() and utilizing some to stop once a match is found:

filteredItems = function (query) {
    var searchTerm = query.toLowerCase();
    return items.filter(item =>
        Object.values(item).some(value => 
            String(value).toLowerCase().includes(searchTerm) 
        )
    );
}

If you prefer to specify the keys to search in:

filteredItems = function (query, keys) {
    var searchTerm = query.toLowerCase();
    return items.filter(item =>
        keys.some(key => 
            String(item[key]).toLowerCase().includes(searchTerm) 
        )
    );
}

Usage example:

filteredItems('Apple', ['fruitName', 'color']);

Answer 2

A more versatile approach would be to create a function that scans through all the properties for a specific string. By iterating through all property values using Object.values() and utilizing some to stop once a match is found:

filteredItems = function (query) {
    var searchTerm = query.toLowerCase();
    return items.filter(item =>
        Object.values(item).some(value => 
            String(value).toLowerCase().includes(searchTerm) 
        )
    );
}

If you prefer to specify the keys to search in:

filteredItems = function (query, keys) {
    var searchTerm = query.toLowerCase();
    return items.filter(item =>
        keys.some(key => 
            String(item[key]).toLowerCase().includes(searchTerm) 
        )
    );
}

Usage example:

filteredItems('Apple', ['fruitName', 'color']);

Answer 3

Answer №2

Another approach is to do it like this:

    In this implementation, the wines array is filtered based on whether any of the properties of each item contain the search value being input. The toLowerCase() method is used to make the comparison case-insensitive.
    this.wines = this.wines.filter((item) => {
                return (item.wineryName.toString().toLowerCase().indexOf(val.toLowerCase()) > -1 ||
                item.wineName.toLowerCase().indexOf(val.toLowerCase()) > -1 ||
                item.wineColor.toLowerCase().indexOf(val.toLowerCase()) > -1);
            })

Answer 4

Another approach is to do it like this:

    In this implementation, the wines array is filtered based on whether any of the properties of each item contain the search value being input. The toLowerCase() method is used to make the comparison case-insensitive.
    this.wines = this.wines.filter((item) => {
                return (item.wineryName.toString().toLowerCase().indexOf(val.toLowerCase()) > -1 ||
                item.wineName.toLowerCase().indexOf(val.toLowerCase()) > -1 ||
                item.wineColor.toLowerCase().indexOf(val.toLowerCase()) > -1);
            })

Answer 5

Answer №3

I was inspired by the solution provided by "trincot" and adapted it for my Angular 5 application:

customFilter(searchTerm, itemList): Observable<IFilteredList> {
  return itemList.filter(item => {
    return Object.values(item).some(val =>
      String(val).includes(searchTerm)
    );
  })
}

Answer 6

I was inspired by the solution provided by "trincot" and adapted it for my Angular 5 application:

customFilter(searchTerm, itemList): Observable<IFilteredList> {
  return itemList.filter(item => {
    return Object.values(item).some(val =>
      String(val).includes(searchTerm)
    );
  })
}

Answer 7

Answer №4

Filter functions correctly. My mistake, upon closer inspection of the question. Filter still functions, but the values also need to be filtered.

let wines = [
    {
        _id: '59a740b8aa06e549918b1fda',
        wineryName: 'Some Winery',
        wineName: 'Pinot Noir',
        wineColor: 'Red',
        imageLink: '/img/FortBerensPN.png'
    },
    {
        _id: '59a7410aaa06e549918b1fdb',
        wineryName: 'Some Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a74125aa06e549918b1fdc',
        wineryName: 'Some Winery',
        wineName: 'Rose',
        wineColor: 'Rose',
        imageLink: '/img/FortBerensRose.png'
    },
    {
        _id: '59a74159aa06e549918b1fdd',
        wineryName: 'Some other Winery',
        wineName: 'Rose',
        wineColor: 'Rose',
        imageLink: '/img/FortBerensRose.png'
    },
    {
        _id: '59a7417aaa06e549918b1fde',
        wineryName: 'Some other Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a8721f4fd43b676a1f5f0d',
        wineryName: 'Some other Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a872244fd43b676a1f5f0e',
        wineryName: 'Winery 3',
        wineName: 'Pinot Noir',
        wineColor: 'Red',
        imageLink: '/img/FortBerensPN.png'
    }
];

let search = (val) => wines.filter(w => Object.values(w).filter(v => v.toLowerCase().indexOf(val.toLowerCase()) !== -1).length > 0);

console.log(search('some'));

Answer 8

Filter functions correctly. My mistake, upon closer inspection of the question. Filter still functions, but the values also need to be filtered.

let wines = [
    {
        _id: '59a740b8aa06e549918b1fda',
        wineryName: 'Some Winery',
        wineName: 'Pinot Noir',
        wineColor: 'Red',
        imageLink: '/img/FortBerensPN.png'
    },
    {
        _id: '59a7410aaa06e549918b1fdb',
        wineryName: 'Some Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a74125aa06e549918b1fdc',
        wineryName: 'Some Winery',
        wineName: 'Rose',
        wineColor: 'Rose',
        imageLink: '/img/FortBerensRose.png'
    },
    {
        _id: '59a74159aa06e549918b1fdd',
        wineryName: 'Some other Winery',
        wineName: 'Rose',
        wineColor: 'Rose',
        imageLink: '/img/FortBerensRose.png'
    },
    {
        _id: '59a7417aaa06e549918b1fde',
        wineryName: 'Some other Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a8721f4fd43b676a1f5f0d',
        wineryName: 'Some other Winery',
        wineName: 'Pinot Gris',
        wineColor: 'White',
        imageLink: '/img/FortBerensPG.png'
    },
    {
        _id: '59a872244fd43b676a1f5f0e',
        wineryName: 'Winery 3',
        wineName: 'Pinot Noir',
        wineColor: 'Red',
        imageLink: '/img/FortBerensPN.png'
    }
];

let search = (val) => wines.filter(w => Object.values(w).filter(v => v.toLowerCase().indexOf(val.toLowerCase()) !== -1).length > 0);

console.log(search('some'));

Answer 9

Answer №5

In my opinion, taking a broader approach might be beneficial:

function filterWinesByKeywords(keys, searchTerm, wines) {

  function extractKeywords(keys, item) {
    let keywords = '';
    keys.forEach(key => {
        keywords += ' ' + item[key];
    });
    return keywords.toLowerCase();
  }

  return wines.filter(wine => {
    const allKeywords = extractKeywords(keys, wine);
    return allKeywords.includes(searchTerm.toLowerCase());
  });
}

Answer 10

In my opinion, taking a broader approach might be beneficial:

function filterWinesByKeywords(keys, searchTerm, wines) {

  function extractKeywords(keys, item) {
    let keywords = '';
    keys.forEach(key => {
        keywords += ' ' + item[key];
    });
    return keywords.toLowerCase();
  }

  return wines.filter(wine => {
    const allKeywords = extractKeywords(keys, wine);
    return allKeywords.includes(searchTerm.toLowerCase());
  });
}

Tips for utilizing filters to search through various key values within an array of objects

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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